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基本上我有一个列表视图,每个列表项为(2 个文本视图和一个复选框)。单击特定列表项时,我想用新的编辑文本视图和一些按钮替换该行。我该如何实施?我应该使用整数变量来存储所选项目的当前位置并加载不同的视图还是使用动作运动事件来获取当前所选项目?

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3 回答 3

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EditViews 实际上是 TextView 的子类,因此您实际上可以在任何地方使用 EditText,然后根据需要设置 edditable=true\false。

只是另一种可能的解决方案,但蒂姆的回答也是合适的。

于 2012-03-29T13:50:01.263 回答
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One possible solution would be to have your row.xml file contain both (2 textviews and a checkbox) and (EditText + some Buttons) But make the EditText and Buttons default to android:visibility="gone" Then you could set an onItemClickListener() for the ListView that will call view.setVisibility() on the proper views to make them visible / invisible. This would appear to the user as though the new items are replacing the old ones in that row of the list.

于 2012-03-29T13:21:42.400 回答
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onItemClick()应该是这样的:

@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
    MyAdapter myAdapter = (MyAdapter) parent.getAdapter();
    MyItem myItem = (MyItem) myAdapter.getItem(position);
    myItem.setSelected(true);  // set selected flag

    // notify the data has been changed and the view should refresh itself
    myAdapter.notifyDataSetChanged();

    // you can obtain the item view type by calling
    // myAdapter.getItemViewType(position);
    ...
}

现在覆盖getViewTypeCount(),getItemViewType()getView()适配器中的方法:

class MyAdapter extends ArrayAdapter<MyItem> {

    private LayoutInflater mInflater;
    private static final int VIEW_ITEM_NORMAL = 0;
    private static final int VIEW_ITEM_SELECTED = 1;
    ...

    @Override
    public int getItemViewType(int position) {
        return getItem(position).isSelected() ? VIEW_ITEM_SELECTED : VIEW_ITEM_NORMAL;
        // implement isSelected()
    }

    @Override
    public int getViewTypeCount() {
        return 2;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View v = convertView;

        int layoutId;
        int viewType = getItemViewType(position);
        if (v == null) {
            switch (viewType) {
                case VIEW_ITEM_NORMAL:
                    layoutId = R.layout.list_item;
                    break;
                case VIEW_ITEM_SELECTED:
                    layoutId = R.layout.list_item_selected;
                    break;
                default:
                    layoutId = R.layout.list_item;
                    break;
            }
            v = mInflater.inflate(layoutId, parent, false);
        } else {
            v = convertView;
        }
        ...

如果只有一项可以同时更改视图,最好将选定标志存储在适配器中:

@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
    MyAdapter myAdapter = (MyAdapter) parent.getAdapter();
    myAdapter.setSelected(position);
    myAdapter.notifyDataSetChanged();
    ...
}

class MyAdapter extends ArrayAdapter<MyItem> {

    private int mSelected = -1;
    ...

    public void setSelected(int position) {
        mSelected = position;
    }

    @Override
    public int getItemViewType(int position) {
        return (mSelected == position) ? VIEW_ITEM_SELECTED : VIEW_ITEM_NORMAL;
    }
    ...

不要忘记应用您可以在这里看到的 ViewHolder 模式。

于 2012-03-29T14:22:39.907 回答