JAVASCRIPT(需要 JQUERY)
function checkmessage(){
$.ajax({
type: "POST",
url: "page.php",
data: "function=getMessages",
success: function(msg){
alert(msg);
if(msg == "noMessage"){
//do nothing
}else{
//should do some validation on error handling
//then use jquery to print msg
}
},
error: function(msg){
alert('Error: cannot load page.');
}
});
setTimeout("checkmessage()",3000);
}
PHP
if($_POST['function'] == "getMessages"){
//fetch info from database
$result = ""
if($result){
//echo it
}else{
echo "noMessage";
}
exit();
}
我只是在没有测试的情况下复制/编辑了它,因此仅将其用作示例/指南
据我所知,这将是最简单的解决方案