2

我正在尝试使用 LDAP 访问我的项目。它成功提示输入用户名和密码，但将正确的凭据放入其中会再次导致提示弹出（似乎凭据错误，但事实并非如此）。

这是我的 security-context.xml：

<?xml version="1.0" encoding="utf-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
             xmlns:beans="http://www.springframework.org/schema/beans"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://www.springframework.org/schema/beans
                                 http://www.springframework.org/schema/beans/spring-beans.xsd
                                 http://www.springframework.org/schema/security
                                 http://www.springframework.org/schema/security/spring-security.xsd">

  <ldap-server url="ldap://${ldap.host}:${ldap.port}/${ldap.root}" manager-dn="${ldap.manager.dn}" manager-password="${ldap.manager.password}" />

  <authentication-manager>
    <ldap-authentication-provider group-search-base="${ldap.group.search.base}" user-search-filter="(uid={0})" user-search-base="${ldap.user.search.base}" />
  </authentication-manager>

  <http use-expressions="true">
    <intercept-url pattern="/**" />
    <http-basic />
  </http>

</beans:beans>

密码存储为 {MD5}hash... 我使用的是 jsr 250 api。

编辑：@TobyHobson 这导致org.xml.sax.SAXParseException; lineNumber: 14; columnNumber: 38; cvc-complex-type.2.4.a: Invalid content was found starting with element 'password-encoder'. One of '{"http://www.springframework.org/schema/security":password-compare}' is expected.

EDIT2：@TobyHobson似乎可以编译，但它仍然拒绝我的正确凭据password-compare。password-encoder

EDIT3：这里是必要的日志：

DEBUG: org.springframework.beans.factory.support.DefaultListableBeanFactory - Returning cached instance of singleton bean 'sessionFactory'
DEBUG: org.springframework.security.web.FilterChainProxy - /licenses/index.html at position 1 of 8 in additional filter chain; firing Filter: 'SecurityContextPersistenceFilter'
DEBUG: org.springframework.security.web.context.HttpSessionSecurityContextRepository - HttpSession returned null object for SPRING_SECURITY_CONTEXT
DEBUG: org.springframework.security.web.context.HttpSessionSecurityContextRepository - No SecurityContext was available from the HttpSession: org.apache.catalina.session.StandardSessionFacade@397af435. A new one will be created.
DEBUG: org.springframework.security.web.FilterChainProxy - /licenses/index.html at position 2 of 8 in additional filter chain; firing Filter: 'BasicAuthenticationFilter'
DEBUG: org.springframework.security.web.authentication.www.BasicAuthenticationFilter - Basic Authentication Authorization header found for user 'demo_admin'
DEBUG: org.springframework.security.authentication.ProviderManager - Authentication attempt using org.springframework.security.ldap.authentication.LdapAuthenticationProvider
DEBUG: org.springframework.security.ldap.authentication.LdapAuthenticationProvider - Processing authentication request for user: demo_admin
DEBUG: org.springframework.security.ldap.search.FilterBasedLdapUserSearch - Searching for user 'demo_admin', with user search [ searchFilter: '(uid={0})', searchBase: 'ou=people', scope: subtree, searchTimeLimit: 0, derefLinkFlag: false ]
DEBUG: org.springframework.security.ldap.SpringSecurityLdapTemplate - Searching for entry under DN 'dc=ubuntu,dc=local', base = 'ou=people', filter = '(uid={0})'
DEBUG: org.springframework.security.ldap.SpringSecurityLdapTemplate - Found DN: uid=demo_admin,ou=people
DEBUG: org.springframework.security.ldap.authentication.PasswordComparisonAuthenticator - Performing LDAP compare of password attribute 'userPassword' for user 'uid=demo_admin,ou=people'
DEBUG: org.springframework.security.web.authentication.www.BasicAuthenticationFilter - Authentication request for failed: org.springframework.security.authentication.BadCredentialsException: Bad credentials
DEBUG: org.springframework.security.web.context.HttpSessionSecurityContextRepository - SecurityContext is empty or contents are anonymous - context will not be stored in HttpSession.
DEBUG: org.springframework.security.web.context.SecurityContextPersistenceFilter - SecurityContextHolder now cleared, as request processing completed

EDIT4：我想这与 jsr 250 api 和组/角色有关。这是我的ldif：

dn: ou=people,dc=ubuntu,dc=local
objectClass: organizationalUnit
ou: people

dn: uid=demo_admin,ou=people,dc=ubuntu,dc=local
userPassword: {MD5}fe01ce2a7fbac8fafaed7c982a04e229
objectClass: posixAccount
objectClass: account
homeDirectory: null
uid: demo_admin
uidNumber: 1001
gidNumber: 1000
cn: Demo Admin

dn: uid=demo_manager,ou=people,dc=ubuntu,dc=local
userPassword: {MD5}fe01ce2a7fbac8fafaed7c982a04e229
objectClass: posixAccount
objectClass: account
homeDirectory: null
uid: demo_manager
uidNumber: 2001
gidNumber: 2000
cn: Demo Manager

dn: uid=demo_viewer,ou=people,dc=ubuntu,dc=local
userPassword: {MD5}fe01ce2a7fbac8fafaed7c982a04e229
objectClass: posixAccount
objectClass: account
homeDirectory: null
uid: demo_viewer
uidNumber: 3001
gidNumber: 3000
cn: Demo Viewer

dn: ou=groups,dc=ubuntu,dc=local
objectClass: organizationalUnit
ou: groups

dn: cn=Admins,ou=groups,dc=ubuntu,dc=local
objectClass: posixGroup
cn: Admins
gidNumber: 1000

dn: cn=Managers,ou=groups,dc=ubuntu,dc=local
objectClass: posixGroup
cn: Managers
gidNumber: 2000

dn: cn=Viewers,ou=groups,dc=ubuntu,dc=local
objectClass: posixGroup
cn: Viewers
gidNumber: 3000

我@RolesAllowed({ Role.ROLE_ADMIN, Role.ROLE_MANAGER, Role.ROLE_VIEWER })在我的控制器中使用，这是我的抽象角色类：

public abstract class Role
{
  public static final String ROLE_ADMIN = "Admins";
  public static final String ROLE_MANAGER = "Managers";
  public static final String ROLE_VIEWER = "Viewers";
}
4

3 回答 3

1

您需要向身份验证提供程序添加密码编码器，以告诉 Spring 在绑定到 LDAP 之前对密码进行哈希处理。例如

<authentication-manager>
  <ldap-authentication-provider group-search-base="${ldap.group.search.base}" user-search-filter="(uid={0})" user-search-base="${ldap.user.search.base}">
    <password-encoder hash="md5"/>
  </ldap-authentication-provider>
</authentication-manager>

如果你使用盐，你还需要包括这个，例如

<password-encoder hash="md5">
  <salt-source user-property="username"/>
</password-encoder>
于 2012-03-12T11:12:24.423 回答
1

不需要在 spring 安全配置文件中定义散列，散列技术将由 ldap 自己处理。您唯一需要做的一件事就是像这样将 MD5 密码存储在 ldap 中......

              Attributes attrs = new BasicAttributes();
      BasicAttribute ocattr = new BasicAttribute("objectclass");
      ocattr.add("top");
      ocattr.add("person");
      ocattr.add("inetorgperson");
      ocattr.add("organizationalperson");
      attrs.put(ocattr);
      attrs.put("sn",user.getName());
      attrs.put("userPassword","{MD5}"+user.getPassword());
于 2013-06-06T14:55:09.840 回答
0

使用绑定身份验证时密码编码方案无关紧要，因为密码检查是在目录中执行的，而不是在 Spring Security 代码中，因此 Spring Security 不需要对密码进行哈希处理，也不需要知道密码是如何存储的。它将以明文形式发送到目录，因此如果您担心的话，应该使用 ldaps 连接。

如果您使用 LDAP“比较”操作进行身份验证，则必须将密码字段的相同副本发送到目录。这很容易出错，因为它取决于大小写是否正确等。目前还没有提供对 {MD5} 哈希的支持，尽管有一个LdapShaPasswordEncoder处理 {SHA} 和 {SSHA}。

您的设置很可能由于其他原因而失败，通过仔细检查调试日志和 LDAP 服务器日志应该可以清楚地看到这一点。

于 2012-03-13T13:50:34.850 回答