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我正在使用 libiptc 通过自定义 c 程序执行 iptables 更新。要求是每 2 秒从一个单独的线程调用 iptc API。

我编写了一个简单的 C 程序来尝试从单独的线程调用 iptc API。c程序粘贴在下面。

/*** thread_iptc.c ***/

#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>

void* thread_func(void* unused)
{
        struct iptc_handle *handle = NULL;
        char *table = "filter";

        while (1)
        {
                printf("\nthread_func(): While loop.\n");
                handle = iptc_init(table);
                if (handle) {
                        printf("thread_func(): handle is not NULL.\n");
                        iptc_free(handle);
                }
                else
                        printf("thread_func(): handle is NULL.\n");

                sleep(2);
        }

        return NULL;
}


int main()
{
        struct iptc_handle *handle = NULL;
        char *table = "filter";
        pthread_t thread_id;

        handle = iptc_init(table);
        if (handle) {
                printf("main(): handle is not NULL.\n");
                iptc_free(handle);
        }
        else
                printf("main(): handle is NULL.\n");


        pthread_create(&thread_id, NULL, &thread_func, NULL);
        pthread_join(thread_id, NULL);

        return 0;
}

我面临的问题是对两者的调用iptc_init(）并且从函数iptc_free()调用时效果很好。main但是，iptc_free()从 调用时，调用失败并出现“分段错误” thread_func()。

程序输出：

# ./test 
main(): handle is not NULL.

thread_func(): While loop.
thread_func(): handle is not NULL.
Segmentation fault

汇编：

# gcc -o test thread_iptc.c -lpthread -lext4 -lext6 -lip4tc -lip6tc -liptc -lxtables -ldl

GDB 回溯

#0  0x00007ffff79be303 in iptc_free () from /lib64/libip4tc.so.0
#1  0x00000000004007f3 in thread_func ()
#2  0x00007ffff7bc77e1 in start_thread () from /lib64/libpthread.so.0
#3  0x00007ffff6efb8ed in clone () from /lib64/libc.so.6

在编译期间或调用新线程时我是否遗漏了什么？

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0 回答 0