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我对这段代码有一个奇怪的问题：如果我如下所示运行它，我会收到错误：

发生了无效的浮点运算。

但是，如果我将参数更改@Longitude为 -98.508730 （请注意仅更改了最后一位），代码就可以正常工作。

该代码应该列出@MilesRadius某个 LatLng 点周围的属性。
@Latitude 和@Longitude 参数与地址表中的经度和纬度字段的类型相同。

我可以在这里做什么？谢谢。

DECLARE @Latitude decimal (10,6);
DECLARE @Longitude decimal (10,6);
DECLARE @MilesRadius int;
SET @Latitude = 29.607654
SET @Longitude = -98.508731
SET @MilesRadius  = 5

SELECT     ADR.LineOne as address, 
           ADR.City as city,           
           ADR.Latitude as latitude,
           ADR.Longitude as longitude, 
           ((3959 * acos(cos(radians(@Latitude)) * cos(radians(ADR.Latitude)) * cos(radians(ADR.Longitude) - radians(@Longitude)) + sin(radians(@Latitude)) * sin(radians(ADR.Latitude))))) as distance
FROM       Shared.Address ADR
WHERE      ADR.Latitude IS NOT NULL AND 
           ADR.Longitude IS NOT NULL AND 
           (3959 * acos(cos(radians(@Latitude)) * cos(radians(ADR.Latitude)) * cos(radians(ADR.Longitude) - radians(@Longitude)) + sin(radians(@Latitude)) * sin(radians(ADR.Latitude)))) < @MilesRadius                       
ORDER BY distance
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1 回答 1

11

您正在使用的唯一返回域错误的函数是ACOS，当输入不在范围内时会发生-1 to +1这种情况，因此您可以摆弄这种情况（我假设中间表达式类似于1.000000000001由于舍入错误）

SELECT     ADR.LineOne as address, 
           ADR.City as city,           
           ADR.Latitude as latitude,
           ADR.Longitude as longitude, 
           distance
FROM       Shared.Address ADR
CROSS APPLY (SELECT cos(radians(@Latitude)) * cos(radians(ADR.Latitude)) * cos(radians(ADR.Longitude) - radians(@Longitude)) + sin(radians(@Latitude)) * sin(radians(ADR.Latitude))) T(ACosInput)
CROSS APPLY (SELECT ((3959 * acos(CASE WHEN ABS(ACosInput) > 1 THEN SIGN(ACosInput)*1 ELSE ACosInput END)))) T2(distance)
WHERE      ADR.Latitude IS NOT NULL AND 
           ADR.Longitude IS NOT NULL AND 
           distance < @MilesRadius                       
ORDER BY distance
于 2012-01-12T15:38:09.023 回答