assembly - IA32 indexed addressing mode without base address

Question

What does this syntax mean? I'm specifically unsure about the missing base address

mov    0x804a1d4(,%edx,4),%eax

score 2 · Accepted Answer

2

将内容分配0x804a1d4 + %edx*4给%eax

于 2011-11-09T04:54:02.053 回答

score 1 · Accepted Answer

没有基础。可以省略基址寄存器或偏移寄存器（但不能同时省略两者）。在这种情况下，基地址是硬编码的，要移动到 eax 的值是从

  0x804a1d4 + (edx * 4)

2 回答 2