0

我有个问题。我一直在寻找一种onclick在标记上获取功能的方法。此标记由 Position 数组构成。但它似乎并没有实现这个onclick功能，如果它实现了，它只适用于最后一个制作的标记。

请问你能帮我吗？

这是数组 

var POIArrayVisited = new Array(
    new Array(52.3764, 4.90245, "De Schreierstoren", "POIone"),
    new Array(52.3727, 4.90036, "De Waag", "POItwo"),
    new Array(52.3737, 4.90012, "Het Zustersklooster", "POIthree"), 
    new Array(52.3750, 4.89939, "Onze lieve heer op solder", "POIfour"), 
    new Array(52.3741, 4.89808, "Belle het standbeeld", "POIfive"));

然后我创建标记： 

// voer de coordinaten van de niet bezochte poi in
// zet markers voor elk POI

var i = 0;
for (i = 0; i < POIArrayVisited.length; i++) {
    var markerLatlng = new google.maps.LatLng(
                    POIArrayVisited[i][0], POIArrayVisited[i][1])
    // Place a hit marker
    markerVisited = new google.maps.Marker({
        position: markerLatlng,
        map: map,
        icon: imageMarkerOld,
        title: POIArrayVisited[i][2]
    });
}

然后它将创建onclick标记。

// For every POI
var i;
for (i = 0; i < POIArrayVisited.length; i++) {
    var POIlinkVisited = POIArrayVisited[i][3];
    var OpenPOI = POIlinkVisited;
    google.maps.event.addListener(markerVisited, "click", function() {
        //link and update cookie
        document.cookie = "OpenPOI" + "=" + OpenPOI;
        window.location.href = "poi.php";
    });

}

我不明白我做错了什么

4

2 回答 2

1

如果您想使用数组并使用链接或 ID 来定义需要在其他页面上打开的内容，您可以使用此 First get you array with

Lat and Long 然后是标题和要使用的值的 ID。

    var POIArrayVisited = new Array(        new Array(52.3764, 4.90245, "De Schreierstoren", "POIone"),
                                            new Array(52.3727, 4.90036, "De Waag", "POItwo"),
                                            new Array(52.3737, 4.90012, "Het Zustersklooster", "POIthree"),
                                            new Array(52.3750, 4.89939, "Onze lieve heer op solder", "POIfour"),
                                            new Array(52.3741, 4.89808, "Belle het standbeeld", "POIfive")
);

这样您就可以使用此代码制作 cookie

// voer de coordinaten van de niet bezochte poi in
                // zet markers voor elk POI
                var i=0;
                for (i=0;i<POIArrayVisited.length;i++) {
                    var markerLatlng = new google.maps.LatLng(POIArrayVisited[i][0],POIArrayVisited[i][1])
                    // Place a hit marker
                    markerVisited = new google.maps.Marker({
                        position:  markerLatlng,
                        map: map,
                        icon: imageMarkerOld,
                        title: POIArrayVisited[i][2],
                        html: POIArrayVisited[i][3]
                    });
                    var OpenPOIVisited = POIArrayVisited[i][3];
                        google.maps.event.addListener(markerVisited, "click", function() {
                            //link and update cookie
                            document.cookie = "OpenPOI"+"="+this.html;
                            window.location.href = "poi.php";
                    });
                }

有了这个，您可以将其用作 php 的 ID

                    // voer de coordinaten van de niet bezochte poi in
                // zet markers voor elk POI
                var i=0;
                for (i=0;i<POIArrayVisited.length;i++) {
                    var markerLatlng = new google.maps.LatLng(POIArrayVisited[i][0],POIArrayVisited[i][1])
                    // Place a hit marker
                    markerVisited = new google.maps.Marker({
                        position:  markerLatlng,
                        map: map,
                        icon: imageMarkerOld,
                        title: POIArrayVisited[i][2],
                        html: POIArrayVisited[i][3]
                    });
                    var OpenPOIVisited = POIArrayVisited[i][3];
                        google.maps.event.addListener(markerVisited, "click", function() {
                            //link and update cookie
                            window.location.href = "poi.php?id="+this.html;
                    });
                }

或者你想引用一个 html 页面

                // voer de coordinaten van de niet bezochte poi in
                // zet markers voor elk POI
                var i=0;
                for (i=0;i<POIArrayVisited.length;i++) {
                    var markerLatlng = new google.maps.LatLng(POIArrayVisited[i][0],POIArrayVisited[i][1])
                    // Place a hit marker
                    markerVisited = new google.maps.Marker({
                        position:  markerLatlng,
                        map: map,
                        icon: imageMarkerOld,
                        title: POIArrayVisited[i][2],
                        html: POIArrayVisited[i][3]
                    });
                    var OpenPOIVisited = POIArrayVisited[i][3];
                        google.maps.event.addListener(markerVisited, "click", function() {
                            //link and update cookie
                            window.location.href = +this.html".html";
                    });

感谢您的帮助！=D

于 2011-10-11T11:06:56.383 回答
0

在您的代码中：

// For every POI
var i;
for (i = 0; i < POIArrayVisited.length; i++) {
    var POIlinkVisited = POIArrayVisited[i][3];
    var OpenPOI = POIlinkVisited;
    google.maps.event.addListener(markerVisited, "click", function() {
        //link and update cookie
        document.cookie = "OpenPOI" + "=" + OpenPOI;
        window.location.href = "poi.php";
    });

}

你从哪里得到一个新的实例markerVisited？据我在您发布的代码片段中看到的，您正在循环，POIArrayVisited但您没有获得markerVisited. 所以这可能是只有LAST标记真正响应点击的原因。

应该类似于：

for (var i = 0; i < POIArrayVisited.length; i++) {
    var markerLatlng = new google.maps.LatLng(POIArrayVisited[i][0], POIArrayVisited[i][1]);
    // Place a hit marker
    var markerVisited = new google.maps.Marker({
        position: markerLatlng,
        map: map,
        icon: imageMarkerOld,
        title: POIArrayVisited[i][2]
    });

    google.maps.event.addListener(markerVisited, "click", function() {
            //link and update cookie
            document.cookie = "OpenPOI" + "=" + OpenPOI;
            window.location.href = "poi.php";
        });

}
于 2011-10-10T17:58:32.987 回答