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当在抓取数据时显示 403 禁止错误时，如何进一步从网站抓取数据

如何抓取数据请指导我我是网络抓取的初学者

import requests, bs4
from bs4 import BeautifulSoup
from csv import writer
url = "https://www.zocdoc.com/gastroenterologists/2"
page = requests.get(url)
page
page.status_code
**403**
page.content
soup = BeautifulSoup(page.content, 'html.parser')
soup
print(soup.prettify())
users = soup.find_all('div', {'data-test': 'search-content'})
 for use in users:
   doctor = use.find('span', attrs={'data-test': 'doctor-card-info-name-full'})#.replace('\n', '')
   specialty = list.find('div', {'data-test': 'doctor-card-info-specialty'})
   #specialty = list.find('div', class_="sc-192nc1l-0 buuGUI overflown")#.text.replace('\n', '')
   #price = list.find('div', class_="listing-search-item__price").text.replace('\n', '')
   #area = list.find('div', class_="listing-search-item__features").text.replace('\n', '')
   info = [doctor] #price, area]
   print(info)

也没有得到输出，在这个网站上没有部分标签来获取或查找所有数据

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1 回答 1

3

在这种情况下，您可以通过以下方式克服 403 错误：

import requests
headers = {
    'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:96.0) Gecko/20100101 Firefox/96.0'}
HOST = 'https://www.zocdoc.com'
PAGE = 'gastroenterologists/2'
with requests.Session() as session:
    (r := session.get(HOST, headers=headers)).raise_for_status()
    (r := session.get(f'{HOST}/{PAGE}', headers=headers)).raise_for_status()
    # process content from here
于 2022-01-31T19:09:44.240 回答