hybris - 如何在hybris HAC中为一个太多的关系编写flexibleSearch查询？

Question

这个不起作用： SELECT *FROM {User as u JOIN Address as a ON {u:a} = {a:pk}} 。

score 2 · Accepted Answer

正如您在关系基数中看到的，所有者作为用户。

所以查询应该是这样的

SELECT *FROM {User as u JOIN Address as a ON {u:pk} = {a:owner}}

score 0 · Accepted Answer

错过了限定符是 "owner" ，通常按照约定将其命名为 type 。选择 {a.PK} 从 {customer as c 加入地址 as a on {c.pk}={a.owner}}

2 回答 2