3

jq 是一个了不起的工具，它做了很多。作为输入我有

[
  {
    "backup": [
      {
        "timestamp": { "start": 1642144383, "stop": 1642144386 },
        "info": {  "size": 1200934840},
        "type": "full"
      },
      {
        "timestamp": {"start": 1642144388, "stop":  1642144392 },
        "info": { "size": 1168586300
        },
        "type": "incr"
      },
      {
        "timestamp": {"start": 1642145388, "stop":  1642145392 },
        "info": { "size": 1168586330
        },
        "type": "incr"
      }
    ],
    "name": "dbname1"
  },
  {
    "backup": [
      {
        "timestamp": { "start": 1642144383, "stop": 1642144386 },
        "info": {  "size": 1200934840},
        "type": "full"
      },
      {
        "timestamp": {"start": 1642144388, "stop":  1642144392 },
        "info": { "size": 1168586300
        },
        "type": "incr"
      }
    ],
    "name": "dbname2"
  }
]

并使用

jq 'map([.backup[] + {name}] | max_by(.timestamp.stop))'

我得到了最新的 timestamp.stop 名称。我应该如何更改它以获取名称和组的最新 timestamp.stop？在 SQL 中，这类似于 max(.timestamp.stop) group by .name,.type 希望输出如下：

[
  {
    "timestamp": {
      "start": 1642144383,
      "stop": 1642144386
    },
    "info": {
      "size": 1200934840
    },
    "type": "full",
    "name": "dbname1"
  },
  {
    "timestamp": {
      "start": 1642145388,
      "stop": 1642145392
    },
    "info": {
      "size": 1168586330
    },
    "type": "incr",
    "name": "dbname1"
  },
  {
    "timestamp": {
      "start": 1642144383,
      "stop": 1642144386
    },
    "info": {
      "size": 1200934840
    },
    "type": "full",
    "name": "dbname2"
  },
  {
    "timestamp": {
      "start": 1642144388,
      "stop": 1642144392
    },
    "info": {
      "size": 1168586300
    },
    "type": "incr",
    "name": "dbname2"
  }
]
4

2 回答 2

2

删除内括号以展平数组，然后删除group_by两个条件（使您的条件成为数组）和map结果max_by数组：

jq 'map(.backup[] + {name}) | group_by([.name, .type]) | map(max_by(.timestamp.stop))'

[
  {
    "timestamp": {
      "start": 1642144383,
      "stop": 1642144386
    },
    "info": {
      "size": 1200934840
    },
    "type": "full",
    "name": "dbname1"
  },
  {
    "timestamp": {
      "start": 1642145388,
      "stop": 1642145392
    },
    "info": {
      "size": 1168586330
    },
    "type": "incr",
    "name": "dbname1"
  },
  {
    "timestamp": {
      "start": 1642144383,
      "stop": 1642144386
    },
    "info": {
      "size": 1200934840
    },
    "type": "full",
    "name": "dbname2"
  },
  {
    "timestamp": {
      "start": 1642144388,
      "stop": 1642144392
    },
    "info": {
      "size": 1168586300
    },
    "type": "incr",
    "name": "dbname2"
  }
]

演示

于 2022-01-18T08:36:01.550 回答
1

这似乎产生了所需的预期输出。.type在执行之前，您需要按记录进行额外分组max_by

map( .backup[] + {name} ) | group_by(.name)[] | 
  group_by(.type) | map(max_by(.timestamp.stop))

jqplay演示

于 2022-01-18T08:36:41.667 回答