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我有一个数据框

   Unnamed: 0                       game score home_odds draw_odds away_odds country                 league             datetime
0           0  Sport Recife - Imperatriz   2:2      1.36      4.31      7.66  Brazil  Copa do Nordeste 2020  2020-02-07 00:00:00
1           1           ABC - America RN   2:1      2.62      3.30      2.48  Brazil  Copa do Nordeste 2020  2020-02-02 22:00:00
2           2  Frei Paulistano - Nautico   0:2      5.19      3.58      1.62  Brazil  Copa do Nordeste 2020  2020-02-02 00:00:00
3           3    Botafogo PB - Confianca   1:1      2.06      3.16       3.5  Brazil  Copa do Nordeste 2020  2020-02-02 22:00:00
4           4          Fortaleza - Ceara   1:1      2.19      2.98      3.38  Brazil  Copa do Nordeste 2020  2020-02-02 22:00:00

我正在执行以下功能

df['game'] = df['game'].astype(str).str.replace('(\(\w+\))', '', regex=True)
df['league'] = df['league'].astype(str).str.replace('(\s\d+\S\d+)$', '', regex=True)
df['game'] = df['game'].astype(str).str.replace('(\s\d+\S\d+)$', '', regex=True)
df[['home_team', 'away_team']] = df['game'].str.split(' - ', expand=True, n=1)
df[['home_score', 'away_score']] = df['score'].str.split(':', expand=True)
df['away_score'] = df['away_score'].astype(str).str.replace('[a-zA-Z\s\D]', '', regex=True)
df['home_score'] = df['home_score'].astype(str).str.replace('[a-zA-Z\s\D]', '', regex=True)
df = df[df.home_score != "."]
df = df[df.home_score != ".."]
df = df[df.home_score != "."]
df = df[df.home_odds != "-"]
df = df[df.draw_odds != "-"]
df = df[df.away_odds != "-"]
m = df[['home_odds', 'draw_odds', 'away_odds']].astype(str).agg(lambda x: x.str.count('/'), 1).ne(0).all(1)
n = df[['home_score']].agg(lambda x: x.str.count('-'), 1).ne(0).all(1)
o = df[['away_score']].agg(lambda x: x.str.count('-'), 1).ne(0).all(1)
df = df[~m]
df = df[~n]
df = df[~o]
df = df[df.home_score != '']
df = df[df.away_score != '']
df = df.dropna()

但是，当我这样做时，我会收到警告：

UserWarning: Boolean Series key will be reindexed to match DataFrame index.
  df = df[~n]
UserWarning: Boolean Series key will be reindexed to match DataFrame index.
  df = df[~o]

我该如何解决这个问题？

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4

1 回答 1

1

我认为您可以尝试更改：

n = df[['home_score']].agg(lambda x: x.str.count('-'), 1).ne(0).all(1)
o = df[['away_score']].agg(lambda x: x.str.count('-'), 1).ne(0).all(1)

至：

n = df['home_score'].str.count('-').ne(0)
o = df['away_score'].str.count('-').ne(0)

它应该是一样的：

n = ~df['home_score'].str.contains('-')
o = ~df['away_score'].str.contains('-')

也应该改变：

df = df[df.home_score != "."]
df = df[df.home_score != ".."]
df = df[df.home_score != "."]
df = df[df.home_odds != "-"]
df = df[df.draw_odds != "-"]
df = df[df.away_odds != "-"]

至：

df = df[~df.home_score.isin([".",".."]) | 
         df[['home_odds','draw_odds','away_odds']].ne("-").any(axis=1)]
于 2021-12-20T05:18:02.930 回答