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我已经实现了一个通过广播发送魔术包的功能。它工作正常,但我想在特殊服务器上接收所有 UDP 广播请求。也可以。但是,如果我尝试读取字节并将字节转换回十六进制(MAC 地址),则 MAC 地址将是错误的。

发送 UDP 请求到:255.255.255.255,MAC = "001a4d5f84f8"

特殊服务器成功接收了 16 次 MAC 地址,但它已经改变:从:001a4d5f84f8 到:001a4d5f3f3f

有任何想法吗?

我的职能:

//Send Packets
//------------------------------------------------------
string MAC_ADDRESS = "001a4d5f84f8";

UdpClient UDP = new UdpClient();
try
{
    IPAddress IPBCast = IPAddress.Parse("255.255.255.255");
    UDP.Client.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.Broadcast, 1);
    int offset = 0;
    byte[] buffer = new byte[512]; 
    //first 6 bytes should be 0xFF
    for (int y = 0; y < 6; y++)
        buffer[offset++] = 0xFF;
    //now repeate MAC 16 times
    for (int y = 0; y < 16; y++)
    {
        int i = 0;
        for (int z = 0; z < 6; z++)
        {
            buffer[offset++] =
            byte.Parse(MAC_ADDRESS.Substring(i, 2), NumberStyles.HexNumber);
            i += 2;
        }
    }
    UDP.EnableBroadcast = true;
    UDP.Send(buffer, 512, new IPEndPoint(IPBCast, 0x1));
}
catch (Exception ex1)
{
    MessageBox.Show(ex1.Message);
    UDP.Close();
}
//Receive Packets
//------------------------------------------------------
Socket sock = new Socket(AddressFamily.InterNetwork,
          SocketType.Dgram, ProtocolType.Udp);
IPEndPoint iep = new IPEndPoint(IPAddress.Any, 0x1);
sock.Bind(iep);

EndPoint ep = (EndPoint)iep;
Console.WriteLine("Ready to receive...");

byte[] data = new byte[1024];
int recv = sock.ReceiveFrom(data, ref ep);

string stringData = Encoding.ASCII.GetString(data, 0, recv);

Console.WriteLine("received: {0}  from: {1}", (StringToHex(stringData)), ep.ToString());
//Convert Received String To Hex
//------------------------------------------------------
public static string StringToHex(string hexstring)
{
    var sb = new StringBuilder();
    foreach (char t in hexstring)
        sb.Append(Convert.ToInt32(t).ToString("x") + " ");
    return sb.ToString();
}
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1 回答 1

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你的问题是Encoding.ASCII.GetString()。它可以读取使用 ASCII 编码的字符串,但这不是您要发送的内容。您必须将字节解码为字节。

如果您希望结果为字符串,您可以使用类似

string.Join("", bytes.Select(b => b.ToString("x2")))

这里,bytes是要转换为字符串的字节序列。

(如果您不在 .Net 4 上,则需要.ToArray()在 . 之后添加Select()。)

于 2011-08-07T15:02:08.813 回答