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我有一个自定义建议来处理从REST API 错误处理复制的控制器的异常以及处理 DataIntegrityViolationException 的方法：

@ExceptionHandler(DataIntegrityViolationException.class)
    protected ResponseEntity<Object> handleDataIntegrityViolation(DataIntegrityViolationException ex,
        WebRequest request) {
    if (ex.getCause() instanceof ConstraintViolationException) {
        return buildResponseEntity(new ApiError(HttpStatus.CONFLICT, "Database error", ex));
    }
    return buildResponseEntity(new ApiError(HttpStatus.INTERNAL_SERVER_ERROR, ex));
}

ApiError - 构造函数

public ApiError(HttpStatus status, String message, Throwable ex) {
        this();
        this.status = status;
        this.message = message;
        this.debugMessage = ex.getLocalizedMessage();
    }

发生错误时，响应会显示如下消息：

  "apierror": {
    "status": "CONFLICT",
    "message": "Database error",
    "debugMessage": "could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement",
    "constraintName": null
  }

问题是消息没有向消费者显示真正的问题，因为真正的问题在 ( ex.getCause().getCause().getMessage()) 内部：

Cannot delete or update a parent row: a foreign key constraint fails 
(`cup_orchestrator`.`cpo_production_cycle`, CONSTRAINT `fk_cpo_production_cycle_cpo_cycle_type1` 
FOREIGN KEY (`cycle_type_id`) REFERENCES `cpo_cycle_type` (`cycle_type_id`))

我想处理这样的消息：“记录仍然有来自其他表的引用”；

是否有任何自定义处理程序异常可以以更具体的方式处理 sql 异常？

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1 回答 1

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我已将 DataIntegrityViolationException 句柄更改为更具体：

@ExceptionHandler(DataIntegrityViolationException.class)
protected ResponseEntity<Object> handleDataIntegrityViolation(DataIntegrityViolationException ex,
                                                                  WebRequest request) {
        Throwable cause = ex.getRootCause();
        if (cause instanceof SQLIntegrityConstraintViolationException) {
            SQLIntegrityConstraintViolationException consEx = (SQLIntegrityConstraintViolationException) cause;
            String message = "";
            String constraint = "";
            HttpStatus httpStatus = null;
            if (consEx.getMessage().contains("UNIQUE")) {
                message = "Cannot enter the same record twice";
                constraint = "DUPLICATED_RECORD";
                httpStatus = HttpStatus.CONFLICT;
            } else if (consEx.getMessage().contains("foreign key constraint")) {
                message = "Record still have reference from other table";
                constraint = "USED_RECORD";
                httpStatus = HttpStatus.UNPROCESSABLE_ENTITY;
            }
            return buildResponseEntity(new ApiError(httpStatus, message, consEx.getMessage(), constraint));
        } else if (ex.getCause() instanceof ConstraintViolationException) {
            return buildResponseEntity(new ApiError(HttpStatus.CONFLICT, "Database error", ex));
        }
        return buildResponseEntity(new ApiError(HttpStatus.INTERNAL_SERVER_ERROR, ex));
    }

我在 ApiError 类和构造函数上创建了一个约束属性来接收：

public ApiError(HttpStatus status, String message, String debugMessage, String constraint) {
        this.status = status;
        this.message = message;
        this.debugMessage = debugMessage;
        this.constraint = constraint;
    }

在反应应用程序将创建一个捆绑到这个约束：
DUPLICATED_RECORD
USED_RECORD

于 2021-10-05T19:11:20.357 回答