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我有一个具有单一服务和单一特征的 BLE 外围设备（Arduino nano）。该特性包含一个 8 位 uint，当开关打开时设置为 1，当开关关闭时设置为 0。该特性支持 READ 和 NOTIFY。

使用 nRF Connect 我可以看到 NOTIFY 部分正在工作，因为当开关状态发生变化时值正在更新。

但我真正想做的是使用 Raspberry Pi 作为使用 Adafruit CircuitPython BLE 的中央设备。

按照 Adafruit CircuitPython BLE 存储库中的示例，我在下面创建了一个简单的程序：

观察_ble_switch.py

#!/usr/bin/env python3

import asyncio
import time
from switch_service import SwitchService

from adafruit_ble import BLERadio
from adafruit_ble.advertising.standard import Advertisement

ble = BLERadio()

async def main():
    device_name = "My Arduino"
    device_found = False
    ble_device_connection = None

    print("Scanning for %r" % device_name)

    while not device_found:
        print("...")

        for adv in ble.start_scan(Advertisement, timeout=5):
            name = adv.complete_name
            if not name:
                continue

            if name.strip("\x00") == device_name:
                ble.stop_scan()
                device_found = True
                print("%r found!" % name)
                ble_device_connection = ble.connect(adv)
                break

    if ble_device_connection and ble_device_connection.connected:
        print("Connected to %r!" % name)

        if SwitchService in ble_device_connection:
            print("switch service available")
            switch_service = ble_device_connection[SwitchService]

            while ble_device_connection.connected:
                print("status %r" % switch_service.read_status())
                time.sleep(0.3)
        else:
            print("switch service not available")

if __name__ == "__main__":
    asyncio.run(main())

switch_service.py

from adafruit_ble.uuid import VendorUUID
from adafruit_ble import Service
from adafruit_ble.characteristics.int import Uint8Characteristic

class SwitchService(Service):
    """
    """

    uuid = VendorUUID('8158b2fd-94e4-4ff5-a99d-9a7980e998d7')

    switch_characteristic = Uint8Characteristic(
        uuid=VendorUUID("8158b2fe-94e4-4ff5-a99d-9a7980e998d7")
    )

    def __init__(self, service=None):
        super().__init__(service=service)
        self.status = self.switch_characteristic

    def read_status(self):
        return self.status

我遇到的问题是 read_status() 将始终返回程序第一次运行时 BLE 开关的状态。它不会收到有关 BLE 开关的后续状态更改的通知。我的想法是，我缺少的是向 BLE 开关注册以收到更改通知。我正在努力寻找示例或参考来做到这一点。

谢谢。

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1 回答 1

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感谢ukBaz指出 Bleak。下面的代码使用了 Bleak，使用起来非常棒。

import asyncio

from bleak import BleakScanner
from bleak.backends.bluezdbus.client import BleakClientBlueZDBus

device_name = "My Arduino"
switch_status_char_uuid = "8158b2fe-94e4-4ff5-a99d-9a7980e998d7"


def notification_handler(sender, data):
    print("Switch is active: {}".format(bool(data[0])))


async def run():
    client = None
    external_heartbeat_received = False
    device = await BleakScanner.find_device_by_filter(
        lambda d, ad: d.name and d.name.lower() == device_name.lower()
    )

    if device is None:
        print("{} not found".format(device_name))
    else:
        print("{} found".format(device))

    client = BleakClientBlueZDBus(device)

    try:
        timer = 60  # seconds

        while timer != 0 or external_heartbeat_received:
            if not client.is_connected:
                if await client.connect():
                    print("Connected to {}".format(device_name))
                    await client.start_notify(switch_status_char_uuid, notification_handler)
            await asyncio.sleep(1)
            timer -= 1

            # If timer expired and we received a heartbeat, restart timer and carry on.
            if timer == 0:
                if external_heartbeat_received:
                    timer = 60
                    external_heartbeat_received = False
    except:
        print("Connected to {} failed".format(device_name))

    if client is not None and client.is_connected:
        await client.disconnect()
        print("Disconnected from {}".format(device_name))

loop = asyncio.get_event_loop()
loop.run_until_complete(run())
于 2021-09-29T10:50:34.353 回答