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我有std::vector<double>, 和我的类型Array。此外， 中有很多数字std::vector<double> source，我想让这段代码以这种方式工作： std::cout << toHisto(source, /* other parameters like min, max, stacks */); 我猜如果该函数toHisto与其他容器一起使用，例如我的Array. 你，我试图这样做，并且模板函数的返回类型有问题Error C3200 'Container<double,std::allocator<double>>': invalid template argument for template parameter 'Container', expected a class template

如果您有任何建议，我将很高兴听到。

代码在这里：

template<template <class T, class Allocator = std::allocator<T>> class Container>
class MyClassForOstream {
public:
    Container<double> &res;
    double min;
    double max;
    MyClassForOstream(Container<double> r, double min_, double max_) : res(r), min(min_), max(max_) {}
    friend std::ostream& operator<< (std::ostream& out, MyClassForOstream const& s) {
        /* sth like for(i in s)"out << s[i]" , and some format stuff from <iomanip>*/
        return out;
    }
};

template<template <class T, class Allocator = std::allocator<T>> class Container>
// Error here at specifing params for  MyClassForOstream < /* here */>
MyClassForOstream<Container<double>> toHisto(Container<double> const& gen, double min, double max, size_t stocks) { // class template must have: operator[], .size(), ctor(size)
    
    Container<size_t> tmp(stocks);
    for (size_t i = 0; i != stocks; ++i) {
        tmp[i] = 0;
    }
    for (size_t i = 0; i != gen.size(); ++i) {
        ++tmp[static_cast<size_t>(((min + gen[i]/(max+min))*((max-min)*stocks)))];
    }  
    Container<double> res(stocks);
    for (size_t i = 0; i != res.size(); ++i) {
        res[i] = 0;
    }
    for (size_t i = 0; i != res.size(); ++i) {
        res[i] = static_cast<double>(tmp[i])/gen.size();
    }

    
   return MyClassForOstream<Container<double>> (res, min, max ); // also error here
}```
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