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我有一系列歌曲，我将它映射到 aFlatList和 onPress 我得到了 song.id 并使用它来查找数组中的特定歌曲并将其传递给TrackPlayer.add()

const songs= [
{
    "artist": "Iglesias",
    "id": "25erfs11",
    "artwork": "https://27mi124bz6zg1hqy6n192jkb-wpengine.netdna-ssl.com/wp-content/uploads/2019/10/Our-Top-10-Songs-About-School-768x569.png",
    "title": "Jola",
    "url": "https://m4a-64.jango.com/21/38/46/2138460792780041793.m4a"
},
{
    "artist": "Version",
    "id": "345asda5",
    "artwork": "https://27mi124bz6zg1hqy6n192jkb-wpengine.netdna-ssl.com/wp-content/uploads/2019/10/Our-Top-10-Songs-About-School-768x569.png",
    "title": "Bueno",
    "url": "https://mp3-128.jango.com/music/20/30/33/2030339267.mp3"
},
{
    "artist": "Lando ",
    "id": "16asasa12",
    "artwork": "https://27mi124bz6zg1hqy6n192jkb-wpengine.netdna-ssl.com/wp-content/uploads/2019/10/Our-Top-10-Songs-About-School-768x569.png",
    "title": "Paul",
    "url": "https://mp3-128.jango.com/music/02/90/05/0290051433.mp3"
},

];

我将它传递给 react-native-track-player 是这样的：

const activeTrack = songs.find((track: Track) => track.id === song.id);
TrackPlayer.add(activeTrack);

我可以通过单击播放不同的歌曲，FlatList但这样做不会让我使用 TrackPlayer.skipToNext() 或 TrackPlayer.skipToPrevious() 功能。有人可以建议我如何使用此功能或自己实现它的方法吗

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