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我想使用 jsonpath 来搜索扁平化 JSON 中的项目。我目前使用这个 Maven 包：

<dependency>
    <groupId>com.jayway.jsonpath</groupId>
    <artifactId>json-path</artifactId>
    <version>2.4.0</version>
</dependency>

从外部来源我得到一个扁平的 json，类似于这个（缩短）：

 "isactive",true
 "article","somemoretester"
 "name.title","Mr"
 "name.first","Corey"
 "name.last","Duncan"
 "name.name","Mr. Corey Duncan"
 "location.street.number",3895
 "location.street.name","Mockingbird Ln"
 "location.city","Birmingham"
 "location.state","Florida"
 "location.timezone.offset","0:00"
 "location.timezone.description","Western Europe Time, London, Casablanca"
 "location.timezone.name","TeaTime"
 "location.timezone.prename","NoTea"
 "location.details.name","B-City"
 "location.details.infratrurcture.publictransport.available",true
 "location.details.infratrurcture.publictransport.name","Birmingtrain"
 "location.details.infratrurcture.publictransport.lines[0].id","B1"
 "location.details.infratrurcture.publictransport.lines[0].name","GreenLine"
 "location.details.infratrurcture.publictransport.lines[0].stations",12
 "location.details.infratrurcture.publictransport.lines[1].id","B2"
 "location.details.infratrurcture.publictransport.lines[1].name","BlueLine"
 "location.details.infratrurcture.publictransport.lines[1].stations",5
 "location.details.infratrurcture.major.name","Mr. Phil Lazio"
 "email","corey.duncan@example.com"
 "login.uuid","33768122-74a6-4457-89ec-e5adeb8c179e"
 "login.username","tinypeacock919"
 "dob.date","1964-07-30T06:19:04.561Z"
 "dob.age",57
 "dob.name","Birthday"
 "nat","US"
 "tags[0][0]","name"
 "tags[0][1]","nat"
 "tags[0][2]","number"
 "tags[1][0]","ibu"
 "tags[1][1]","infratrurcture"
 "tags[1][2]","isactive"
 "tags[2][0]","cell"
 "tags[2][1]","coordinates"
 "tags[2][2]","country"
 "tags[3][0]","id"
 "tags[3][1]","irrelevant"
 "tags[3][2]","infos"
 "secrets[0][0][0].name","example1"
 "secrets[0][0][0].value","nothing"
 "secrets[0][0][1].name","example2"
 "secrets[0][0][1].value","same"
 "secrets[0][1][0].name","oof"
 "secrets[0][1][0].value","ofo"
 "secrets[0][1][1].name","java"
 "secrets[0][1][1].value","nojava"
 "secrets[0][2][0].name","stuff"
 "secrets[0][2][0].value","things"
 "secrets[0][2][1].name","foo"
 "secrets[0][2][1].value","bar"

有什么方法可以将此扁平化输入与 json-path 库一起使用？我试过类似的东西：

JsonPath.parse(flattenedjson, Configuration.defaultConfiguration()).read("$..name")

但是没有结果。如果我使用 JSON-unflattener 并使用：

JsonPath.parse(JsonUnflattener.unflatten(flattenedjson), Configuration.defaultConfiguration()).read("$..name")

它会像魅力一样工作......但是这个不平坦的步骤会花费很多时间。有什么方法可以让我的第一个 cvode 示例工作吗？

作为附加问题。作为方法的结果，有什么方法可以获得完整的json read()？read()或者是通过两次调用获得“完整 JSON”的唯一方法（一个有Option.AS_PATH_LIST一个没有这个选项）并将这两个结果合并到一个浮动列表中，就像上面一样，最后一步将它展平以获得“正常”JSON ?

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1 回答 1

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扁平化版本将部分作为字符串。这些是 JSON 中的合法密钥，因此在使用大多数工具时，您必须将这些密钥指定为展平状态。

正如您所展示的那样使用“unflattener”可能是您最好的选择。

关于你的其他问题，我对这个库并不特别熟悉，所以恐怕在那里我帮不上什么忙。

于 2021-06-30T19:16:22.513 回答