我的网站上有一个日历,它获取开始日期和结束日期,并将它们传递给计算 . 让我们有开始日期Mon Mar 29 2021 03:00:00 GMT+0300 (Eastern European Summer Time)
,结束日期是Mon Apr 05 2021 03:00:00 GMT+0300 (Eastern European Summer Time)
;这个函数应该返回 ["30/3/2021","31/3/2021","1/4/2020","2/4/2020","3/4/2020","4/4/ 2020"]
let getDatesInRange = (start, end) => {
let dates = ref([])
let current = ref(start)
while current.contents <= end {
dates := dates.contents->Js.Array2.concat([current.contents->toUTCDateString])
current := {
let date = current.contents->toUTCDateString->Js.Date.fromString
date->Js.Date.setDate(date->Js.Date.getDate +. 1.0)->ignore
date
}
}
dates.contents
}
这是 toUTCDateString 函数,它接受一个日期并给出它的字符串版本
let toUTCDateString = date => {
let date = date->External.unSafeCastToJsObject
date["toISOString"]()["split"]("T")[0]
}
这些功能在夏令时更改之前工作正常;我们获得了一个小时,所以一天因为某种原因停留在那里 任何机构之前都面临过这个问题,谁来处理这样的时间问题?