0

我有一个嵌套的 promise，它获取数据然后将其呈现给 DOM。

我正在尝试将其转换为 async/await 语法，但是因为它嵌套了 Promise.All 我在转换它时遇到了麻烦。

    fetch(searchUrl)
        .then(function (response) {
          return response.json()
        })
        .then(function (data) {
          searchLoader.style.display = "none";
          for (let i = 0; i < 10; i++) {
            let stock = `${data[i].name}, (${data[i].symbol})`;
            listOfStocks.innerHTML += `<li class="list-group-item"><a href="./company.html?symbol=${data[i].symbol}">${stock}<a/></li>`;
            // console.log(data[i].symbol)
          }
          return Promise.all(data.map(item => fetch(`${BaseUrl}company/profile/${item.symbol}`)));
        })
        .then(function (response) {
          return Promise.all(response.map(x => x.json()));
        })
        .then(function (data1) {
          console.log(data1);
          for (let i = 0; i < listOfStocks.children.length; i++) {
            if (data1[i].profile.changes >= 0) {
              listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc" style="color:green;"> ${data1[i].profile.changesPercentage}</span>`;
            } else {
              listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc"> ${data1[i].profile.changesPercentage}</span>`;
            }
          }

谢谢

4

3 回答 3

1

它似乎正在工作@bergi - 感谢您的指针

  const response = await fetch(searchUrl);
      const data = await response.json();

      searchLoader.style.display = "none";
      for (let i = 0; i < 10; i++) {
        let stock = `${data[i].name}, (${data[i].symbol})`;
        listOfStocks.innerHTML += `<li class="list-group-item"><a href="./company.html?symbol=${data[i].symbol}">${stock}<a/></li>`;
        // console.log(data[i].symbol)
      }
      const response1 = await Promise.all(data.map(item => fetch(`${BaseUrl}company/profile/${item.symbol}`)));

      const data1 = await Promise.all(response1.map(x => x.json()));

      for (let i = 0; i < listOfStocks.children.length; i++) {
        if (data1[i].profile.changes >= 0) {
          listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc" style="color:green;"> ${data1[i].profile.changesPercentage}</span>`;
        } else {
          listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc"> ${data1[i].profile.changesPercentage}</span>`;
        }
      }
    ```
于 2021-02-28T13:44:33.397 回答
0

这就是您将Promise.then(...).then(...).then(....)链转换为async/await代码的方式：-

async function processStuff(){
  const data = await fetch(searchUrl).then((response)=>response.json());

  searchLoader.style.display = "none";

       for (let i = 0; i < 10; i++) {
            let stock = `${data[i].name}, (${data[i].symbol})`;
            listOfStocks.innerHTML += `<li class="list-group-item"><a href="./company.html?symbol=${data[i].symbol}">${stock}<a/></li>`;
            // console.log(data[i].symbol)
          }
          const response = await Promise.all(data.map(item => fetch(`${BaseUrl}company/profile/${item.symbol}`)));

          const data1 = await Promise.all(response.map(x => x.json()));

               for (let i = 0; i < listOfStocks.children.length; i++)             {
            if (data1[i].profile.changes >= 0) {
              listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc" style="color:green;"> ${data1[i].profile.changesPercentage}</span>`;
            } else {
              listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc"> ${data1[i].profile.changesPercentage}</span>`;
            }  
          
            }

}
processStuff();

注意 - 我在这里没有什么特别的，Promise.all()因为它只是返回一个Promise. 如果只是Promise.resolve(2)，方法将是相同的。

于 2021-02-28T13:34:39.050 回答
0

应该是这样的：

try {
  const response = await fetch(searchURL)
  const data = await response.json()
  searchLoader.style.display = "none";
  for (let i = 0; i < 10; i++) {
    let stock = `${data[i].name}, (${data[i].symbol})`;
    listOfStocks.innerHTML += `<li class="list-group-item"><a href="./company.html?symbol=${data[i].symbol}">${stock}<a/></li>`;
    // console.log(data[i].symbol)
  }
  const data1 = await Promise.all(data.map(async (item) => {
    const response = await fetch(`${BaseUrl}company/profile/${item.symbol}`)
    return response.json()
  }));
  for (let i = 0; i < listOfStocks.children.length; i++) {
    if (data1[i].profile.changes >= 0) {
      listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc" style="color:green;"> ${data1[i].profile.changesPercentage}</span>`;
    } else {
      listOfStocks.children[i].innerHTML = `<img class="logo-for-list" src="${data1[i].profile.image}" /> ${listOfStocks.children[i].innerHTML} <span class="color-prc"> ${data1[i].profile.changesPercentage}</span>`;
    }
  }
} catch (e) {
  console.log(e)
}

于 2021-02-28T13:34:51.343 回答