1

以下工作将 Swagger json 解析为资源、方法、httptype 但可能...... $path.Definition 部分很奇怪，我怎样才能让 $path.Definition 成为一个数组而不是我需要解析的字符串数组符号。

$json = Get-Content -Path "$PSScriptRoot/Test/example_swagger.json" | ConvertFrom-Json
$paths = Get-Member -InputObject $json.paths -MemberType NoteProperty
$result = ""
foreach($path in $paths) {
    $elements = $path.Name.Substring(5).split("/") -join ","
    $httpmethods = $path.Definition.Substring($path.Definition.IndexOf("@{"))
    if ($httpmethods.Contains("get")) {
        $result += $elements + ", GET" + "`n"
    }
    if ($httpmethods.Contains("post")) {
        $result += $elements + ", POST" + "`n" #same methodnames different http methods
    }
}
$result
4

1 回答 1

2

正如我对通过 JSON 文件 PowerShell 进行迭代的回答中所详述的那样，的输出ConvertFrom-Json很难迭代。这使得“对于对象中的每个键”和“对象的键不提前知道”类型的情况更难以处理，但并非不可能。

你需要一个辅助函数：

# helper to turn PSCustomObject into a list of key/value pairs
function Get-ObjectMember {
    [CmdletBinding()]
    Param(
        [Parameter(Mandatory=$True, ValueFromPipeline=$True)]
        [PSCustomObject]$obj
    )
    $obj | Get-Member -MemberType NoteProperty | ForEach-Object {
        $key = $_.Name
        [PSCustomObject]@{Key = $key; Value = $obj."$key"}
    }
}

有了这个，方法变得简单多了：

$swagger = Get-Content -Path "example_swagger.json" -Encoding UTF8 -Raw | ConvertFrom-Json

$swagger.paths | Get-ObjectMember | ForEach-Object {
    [pscustomobject]@{
        path = $_.Key
        methods = $_.Value | Get-ObjectMember | ForEach-Object Key
    }
}

应用到来自https://editor.swagger.io/的默认 Swagger 文件作为示例，打印出来

path                     methods            
----                     -------            
/pet                     {post, put}        
/pet/findByStatus        get                
/pet/findByTags          get                
/pet/{petId}             {delete, get, post}
/pet/{petId}/uploadImage post               
/store/inventory         get                
/store/order             post               
/store/order/{orderId}   {delete, get}      
/user                    post               
/user/createWithArray    post               
/user/createWithList     post               
/user/login              get                
/user/logout             get                
/user/{username}         {delete, get, put}
于 2021-02-06T09:22:42.047 回答