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我能够通过 COM 库 FaxComLib（添加参考 -> COM 选项卡 ->faxcom 1.0 类型库）发送传真，并且传真成功通过。

我的问题是，虽然我可以发送传真，但我似乎无法从传真队列中获得准确的状态。FaxJob 对象的 QueueStatus 属性始终返回“Pending”。

环境：Windows 2003 R2 Enterprise w/SP2——也曾在 Windows 2008 R2 上进行过尝试，结果相同

这是我的原型代码：

    public void GetFaxStatus(int queueNum)
    {
        FaxServer faxServer = new FaxServer();
        faxServer.Connect("myfaxservername");
        bool isInQueue = false;

        FaxJobs faxJobs = (FaxJobs)faxServer.GetJobs();

        for (int i = 1; i <= faxJobs.Count; i++)
        {
            FaxJob j = (FaxJob)faxJobs.Item[i];
            MessageBox.Show(faxJobs.Item[i].GetType().ToString() + "\r\n" + CreateStatus(j));

            if (j.JobId == queueNum)
            {
                MessageBox.Show("Found Job:\r\n" + CreateStatus(j));
                isInQueue = true;
            }

        }

        if (isInQueue == false)
        {
            MessageBox.Show("Fax is no longer in queue.(...or does not exist)");
        }

        faxServer.Disconnect();
    }

    static string CreateStatus(FaxJob job)
    {
        StringBuilder sb = new StringBuilder();

        sb.AppendLine(string.Format("Billing Code: {0}", job.BillingCode));
        sb.AppendLine(string.Format("Device Status: {0}\r\n", job.DeviceStatus));
        sb.AppendLine(string.Format("Queue Status: {0}", job.QueueStatus));
        sb.AppendLine(string.Format("Display Name: {0}", job.DisplayName));
        sb.AppendLine(string.Format("Fax Number: {0}", job.FaxNumber));
        sb.AppendLine(string.Format("Job Id: {0}", job.JobId));
        sb.AppendLine(string.Format("Tsid: {0}", job.Tsid));
        sb.AppendLine(string.Format("Type: {0}", job.Type));
        sb.AppendLine(string.Format("Page Count: {0}", job.PageCount));

        return sb.ToString();
    }

当我为失败的作业运行它（超过重试限制）时，我得到了这个：

无论作业的真实状态如何，始终返回此结果。

这是我在任何传真工作中获得的唯一身份；在任何状态。难道我做错了什么？传真服务器是否配置错误？你能帮我解释一下我的问题吗？

谢谢。-杰森

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2 回答 2

2

我发现传真状态最可靠的是使用“Microsoft 传真服务扩展 COM 类型”库。添加对 COM 库的引用后，您可以侦听详细说明传真服务器发生情况的状态事件。

我编写了一个FaxServerListener类，该类注册对侦听很重要的事件，其中一个事件包括一个FaxJobStatus包含相关状态属性的对象。

这是您注册该OnOutgoingJobChanged活动然后收听它的操作。

// ...
using FAXCOMEXLib;

public class FaxServerListener
{
    private FaxServer faxServer;

    public FaxServerListener(string faxServerMachineName)
    {
        faxServer = new FaxServer();
        faxServer.Connect(faxServerMachineName);
        RegisterFaxServerEvents();
    }

    private void RegisterFaxServerEvents()
    {
        // subscribe to multiple FaxServer events here ...
        faxServer.OnOutgoingJobChanged += faxServer_OnOutgoingJobChanged;

        /* very important, you MUST tell the FaxServer object which events you're
         * listening for, otherwise the events will never raise!
         * This is what I have set and you should only need one of the event types
         * to listen for but I didn't research this for your problem
         */
        var events = FAX_SERVER_EVENTS_TYPE_ENUM.fsetACTIVITY |
                     FAX_SERVER_EVENTS_TYPE_ENUM.fsetDEVICE_STATUS |
                     FAX_SERVER_EVENTS_TYPE_ENUM.fsetOUT_ARCHIVE |
                     FAX_SERVER_EVENTS_TYPE_ENUM.fsetOUT_QUEUE;

        faxServer.ListenToServerEvents(events);
    }

    private void faxServer_OnOutgoingJobChanged(FaxServer faxServer, string jobId,
        FaxJobStatus jobStatus)
    {
        // Of course you can do whatever you wish here. This is the method that
        // subscribes to the event with a JobStatus object
        string output = string.Format("Outgoing Job Changed -> {0}{1}{2}",
            jobId, Environment.NewLine, GetJobStatusOutput(jobStatus));

        // you could process the FaxJobStatus object how ever you wish here
        // I raised another event from this listener class with the output data
        // for other client code to listen to.
    }

    private string GetJobStatusOutput(FaxJobStatus jobStatus)
    {
        StringBuilder sb = new StringBuilder();

        sb.AppendLine("\tDeviceID: " + jobStatus.DeviceId.ToString());
        sb.AppendLine("\tCurrent Page: " + jobStatus.CurrentPage.ToString());
        sb.AppendLine("\tExt. Status Code: " + jobStatus.ExtendedStatusCode.ToString());
        sb.AppendLine("\tExt. Status: " + jobStatus.ExtendedStatus);
        sb.AppendLine("\tJob Type: " + jobStatus.JobType.ToString());
        sb.AppendLine("\tRetries: " + jobStatus.Retries.ToString());
        sb.AppendLine("\tSize: " + jobStatus.Size.ToString());
        sb.AppendLine("\tStatus: " + jobStatus.Status.ToString());
        sb.AppendLine("\tStart: " + jobStatus.TransmissionStart.ToShortTimeString());

        if (jobStatus.ExtendedStatusCode != FAX_JOB_EXTENDED_STATUS_ENUM.fjesTRANSMITTING)
        {
            sb.AppendLine("\tStop: " + jobStatus.TransmissionEnd.ToShortTimeString());
        }

        sb.AppendLine("\tTSID: " + jobStatus.TSID);

        return sb.ToString();
    }

}

这是此代码的一些示例输出

Outgoing Job Changed -> 201cce11ee0903f
    DeviceID: 65538
    Current Page: 1
    Ext. Status Code: fjesCALL_COMPLETED
    Ext. Status: 
    Job Type: fjtSEND
    Retries: 0
    Size: 10841
    Status: fjsINPROGRESS
    Start: 3:20 PM
    Stop: 3:21 PM
    TSID: Fax

如您所见，它仍然显示您提到的待处理传真状态，但 ExtendedStatusCode 枚举值提供了更好的状态。

此处引用了有关每个扩展状态代码的详细状态信息。

于 2012-02-01T21:02:34.827 回答
0

所以，我想不出任何实质性的东西，但我已经取得了一点进展。如果您在检查状态之前调用 FaxJob.Refresh()，您会得到更好的结果。似乎在大多数情况下，您仍然会获得无用的状态（在我的情况下为“未知”），但至少它并不总是“待定”。如果传真失败，这也会返回“Retries Exceeded”状态，但否则，“未知”是您可以获得的唯一状态，我猜。

这是一些示例代码：

        if (j.JobId == queueNum)
        {
            MessageBox.Show("Found Job:\r\n" + CreateStatus(j));
            j.Refresh();
            isInQueue = true;
        }
于 2011-07-21T13:55:09.173 回答