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目标aws_athena_named_query使用 terraform 创建两个资源。每个查询的配置在单独的字典中定义。所有查询字典都嵌套在一个列表中（参见query_dict变量）。

variable query_dict {
    default = [
        {
            name = "query1"
            workgroup = "bar"
            query = "SELECT * FROM foo"   
        },
        {
            name = "query2"
            workgroup = "bar"
            query = "SELECT * FROM baz"   
        }
    ]
}

resource "aws_athena_named_query" "olap" {
  for_each = toset([for query in var.query_dict: {
            name   = query.name
            workgroup = query.workgroup
            query = query.query}])
  name = each.value.name
  query = each.value.query
  database = "test"
  workgroup = each.value.workgroup
}

导致错误：

The given "for_each" argument value is unsuitable: "for_each" supports maps
and sets of strings, but you have provided a set containing type object.

尝试2：

resource "aws_athena_named_query" "olap" {
  for_each = [for query in tomap(var.query_dict): {
            name   = query.name
            workgroup = query.workgroup
            query = query.query}]
  name = each.value.name
  query = each.value.query
  database = "test"
  workgroup = each.value.workgroup
}

结果是：

Invalid value for "v" parameter: cannot convert tuple to map of any single
type.

尝试 3：

resource "aws_athena_named_query" "olap" {
  count = length(var.query_dict)
  name = query_dict[count.index]["name"]
  query = query_dict[count.index]["query"]
  database = "test"
  workgroup = query_dict[count.index]["workgroup"]
}

输出错误：

  on main.tf line 57, in resource "aws_athena_named_query" "olap":
  57:   workgroup = query_dict[count.index]["workgroup"]

A reference to a resource type must be followed by at least one attribute
access, specifying the resource name.

预期输出：

# aws_athena_named_query.olap["query1"] will be created
  + resource "aws_athena_named_query" "olap" {
      + database  = "db"
      + id        = (known after apply)
      + name      = "query1"
      + query     = "SELECT * FROM foo"
      + workgroup = "bar"
    }

# aws_athena_named_query.olap["query2"] will be created
  + resource "aws_athena_named_query" "olap" {
      + database  = "db"
      + id        = (known after apply)
      + name      = "query2"
      + query     = "SELECT * FROM baz"
      + workgroup = "bar"
    }
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2 回答 2

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我认为以下应该有效：

resource "aws_athena_named_query" "olap" {

  for_each = {for idx, query in var.query_dict: idx => query}
  
  name = each.value.name
  query = each.value.query
  database = "test"
  workgroup = each.value.workgroup
}

在上面，您创建地图idx作为键：

{
  "0" = {
    "name" = "query1"
    "query" = "SELECT * FROM foo"
    "workgroup" = "bar"
  }
  "1" = {
    "name" = "query2"
    "query" = "SELECT * FROM baz"
    "workgroup" = "bar"
  }
}
于 2020-08-07T07:04:47.390 回答
0

在这种情况下不需要使用for_each，因为您实际上是在迭代一个列表。您可以使用count：

resource "aws_athena_named_query" "olap" {
  count = length(var.query_dict)
  name = var.query_dict[count.index]['name']
  query = var.query_dict[count.index]['query']
  database = "test"
  workgroup = var.query_dict[count.index]['workgroup']
}
于 2020-08-07T15:48:23.443 回答