[![从基点位置移动到测量点时的正确位置][2]][2]
我正在编写一个程序以在 Revit 中显示 navisworks 冲突点,但是,当基点不是 (0,0,0) 时,我发现很难将它们放置在确切的位置。当我手动将位置差异添加到代码中时,它可以工作。如何以编程方式解决此问题?我知道可能有一个简单的计算要解决,但我似乎无法弄清楚。我从谷歌上搜索了一些想法,但无济于事。任何想法如何去做?
public static XYZ WorldToLocal(Document document, XYZ coordinate, bool millimeters)
{
ElementCategoryFilter filter = new ElementCategoryFilter(BuiltInCategory.OST_ProjectBasePoint);
FilteredElementCollector collector = new FilteredElementCollector(document);
IList<Element> oProjectBasePoints = collector.WherePasses(filter).ToElements();
Element oProjectBasePoint = null;
foreach (Element bp in oProjectBasePoints)
{
oProjectBasePoint = bp;
break;
}
double x = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_EASTWEST_PARAM).AsDouble();
double y = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_NORTHSOUTH_PARAM).AsDouble();
double z = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_ELEVATION_PARAM).AsDouble();
double r = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_ANGLETON_PARAM).AsDouble();
XYZ result = new XYZ(
coordinate.X * Math.Cos(r) - coordinate.Y * Math.Sin(r) ,
coordinate.X * Math.Sin(r) + coordinate.Y * Math.Cos(r),
coordinate.Z);
//Code that makes it work
XYZ newpostion = new XYZ(result.X - 21.943, result.Y +13.410, result.Z);
//ends here
if (millimeters)
{
return newpostion * 304.8;
}
return newpostion;
}