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无需手动移动的位置

[![从基点位置移动到测量点时的正确位置][2]][2]

基点距测量点的尺寸

我正在编写一个程序以在 Revit 中显示 navisworks 冲突点,但是,当基点不是 (0,0,0) 时,我发现很难将它们放置在确切的位置。当我手动将位置差异添加到代码中时,它可以工作。如何以编程方式解决此问题?我知道可能有一个简单的计算要解决,但我似乎无法弄清楚。我从谷歌上搜索了一些想法,但无济于事。任何想法如何去做?

public static XYZ WorldToLocal(Document document, XYZ coordinate, bool millimeters)
        {
            ElementCategoryFilter filter = new ElementCategoryFilter(BuiltInCategory.OST_ProjectBasePoint);
            FilteredElementCollector collector = new FilteredElementCollector(document);
            IList<Element> oProjectBasePoints = collector.WherePasses(filter).ToElements();

            Element oProjectBasePoint = null;

            foreach (Element bp in oProjectBasePoints)
            {
                oProjectBasePoint = bp;
                break;
            }

            double x = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_EASTWEST_PARAM).AsDouble();
            double y = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_NORTHSOUTH_PARAM).AsDouble();
            double z = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_ELEVATION_PARAM).AsDouble();
            double r = oProjectBasePoint.get_Parameter(BuiltInParameter.BASEPOINT_ANGLETON_PARAM).AsDouble();

            XYZ result = new XYZ(
             coordinate.X * Math.Cos(r) - coordinate.Y * Math.Sin(r) ,
             coordinate.X * Math.Sin(r) + coordinate.Y * Math.Cos(r),
             coordinate.Z);

//Code that makes it work
            XYZ newpostion = new XYZ(result.X - 21.943, result.Y +13.410, result.Z);
//ends here
            if (millimeters)
            {
                return newpostion * 304.8;
            }
            return newpostion; 

        }
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1 回答 1

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这会将测量点的位置返回到基点。解决我的问题。

   IEnumerable<BasePoint> points = new FilteredElementCollector(document)
                .OfClass(typeof(BasePoint))
                .Cast<BasePoint>();

            XYZ surveypointXYZ = new XYZ();
            foreach (BasePoint bp in points)
            {
                if (bp.IsShared)
                {
                    BoundingBoxXYZ bb = bp.get_BoundingBox(null);
                    surveypointXYZ = bb.Min;

                }
            }
于 2020-07-04T21:59:22.297 回答