1

我对 SQL 真的很陌生，这样做是为了满足我的基本工作需求，基本上我不是技术人员。但我很想知道这里有什么方法可以简化我的 SQL 代码：

SET sql_mode = '';


SELECT DISTINCT partner.kode_agent,
                institusi.nama,
                count(proposal.kode_proposal) AS 'Jumlah Proposal',
                sum(project.jumlah_pencairan) AS 'Jumlah Pencairan'
FROM brw_proposals proposal
JOIN ms_agent partner ON proposal.kode_agent = partner.kode_agent
JOIN ms_agent_institusi institusi ON partner.kode_institusi = institusi.kode_institusi
JOIN ms_projects project ON proposal.kode_proposal = project.kode_proposal
WHERE institusi.nama like 'BMT%' and proposal.status_proposal_id = 4
  OR institusi.nama like 'BMT%' and proposal.status_proposal_id = 8
  OR institusi.nama like 'BMT%' and proposal.status_proposal_id = 3
  OR institusi.nama like 'BMT%' and proposal.status_proposal_id = 10
  OR institusi.nama like 'Baitul Maal Wat%' and proposal.status_proposal_id = 4
  OR institusi.nama like 'Baitul Maal Wat%' and proposal.status_proposal_id = 8
  OR institusi.nama like 'Baitul Maal Wat%' and proposal.status_proposal_id = 3
  OR institusi.nama like 'Baitul Maal Wat%' and proposal.status_proposal_id = 10
  OR institusi.nama like 'Ksp%' and proposal.status_proposal_id = 4
  OR institusi.nama like 'Ksp%' and proposal.status_proposal_id = 8
  OR institusi.nama like 'Ksp%' and proposal.status_proposal_id = 3
  OR institusi.nama like 'Ksp%' and proposal.status_proposal_id = 10
GROUP BY institusi.nama

因为我猜 WHERE 子句太多了，而且我对子查询不太熟悉。

希望任何人都可以分享他们的经验来改进我的代码！谢谢

4

2 回答 2

3

这是简化的查询：

SELECT DISTINCT partner.kode_agent,
                institusi.nama,
                count(proposal.kode_proposal) AS 'Jumlah Proposal',
                sum(project.jumlah_pencairan) AS 'Jumlah Pencairan'
FROM brw_proposals proposal
JOIN ms_agent partner ON proposal.kode_agent = partner.kode_agent
JOIN ms_agent_institusi institusi ON partner.kode_institusi = institusi.kode_institusi
JOIN ms_projects project ON proposal.kode_proposal = project.kode_proposal
WHERE (institusi.nama like 'BMT%' OR institusi.nama like 'Ksp%' OR institusi.nama like 'Baitul Maal Wat%') and proposal.status_proposal_id IN (4,8,3,10)
GROUP BY institusi.nama

您可以使用IN子句来匹配多个值，例如

proposal.status_proposal_id IN (4,8,3,10)
于 2020-06-07T15:17:53.520 回答
0

这是一个有效查询的示例。没有足够的信息来说明它是否满足您的要求......

SELECT p.kode_agent
     , i.nama
     , COUNT(k.kode_proposal) 'Jumlah Proposal'
     , SUM(j.jumlah_pencairan) 'Jumlah Pencairan'
  FROM brw_proposals k
  JOIN ms_agent p 
    ON k.kode_agent = p.kode_agent
  JOIN ms_agent_institusi i
    ON i.kode_institusi = p.kode_institusi 
  JOIN ms_projects j
    ON k.kode_proposal = j.kode_proposal
 WHERE k.status_proposal_id IN(4,8,3,10)
   AND ( i.nama like 'BMT%'
      OR i.nama like 'Baitul Maal Wat%'
      OR i.nama like 'Ksp%' 
       )
 GROUP 
    BY i.nama
     , p.kode_agent;
于 2020-06-07T15:32:30.933 回答