我正在尝试使用条件“ccode”=“Ticker”、“Date”=“Date”和“Time”=“Timestamp”合并两个表。但是,如果“时间”不完全匹配,则应查看“Timeint”(最多 -2 分钟)。因为这是我不能做的事情left_join
——我在想fuzzy_left_join
。
我遇到两个问题:
- 我的数据存储在 bigquery 上,我可以做一个
left_join
工作。但是,当我尝试 a 时fuzzy_left_join
,我收到以下错误消息:
“错误:tibble 中的所有列都必须是 1d 或 2d 对象:* Column
col
为 NULL
- 我试图制作一个可重现的样本(这有点不同,因为它没有存储为 2 的列表),它也不起作用。
这是一个可重现的示例:
library(fuzzyjoin)
library(anytime)
calls.sample <- data.frame(ccode = c("MMM", "K", "A", "CAG", "PM"),
Date = c(20111020, 20111021, 20120102, 20110510, 20080710),
Time = c("09:30:00", "14:30:00", "11:00:00", "15:30:00", "13:00:00"),
Timeint = c("9:28:00", "14:28:00", "10:58:00", "15:28:00", "12:58:00")
)
str(calls.sample$Time)
calls.sample$Time <- as_hms(as.character(calls.sample$Time))
calls.sample$Timeint <- as_hms(as.character(calls.sample$Timeint))
stocks.sample <- data.frame(Ticker = c("MMM", "K", "A", "CAG", "PM"),
Date = c(20111020, 20111021, 20120102, 20110510, 20080710),
Timestamp = c("9:28:00", "14:30:00", "11:00:00", "15:30:00", "13:00:00"),
OpenPrice = c(5, 1,6,7,8))
stocks.sample$Timestamp <- as_hms(as.character(stocks.sample$Timestamp))
fuzzy_left_join(
calls.sample, stocks.sample,
by = c(
"ccode" = "Ticker",
"Date" = "Date",
"Time" = "Timestamp",
"Timeint" = "Timestamp"
),
match_fun = list(`==`, `==`, `<=`, `>=`)
)
我在寻找:
ccode Date Time OpenPrice
1 MMM 20111020 09:30:00 5
2 K 20111021 14:30:00 1
3 A 20120102 11:00:00 6
4 CAG 20110510 15:30:00 7
5 PM 20080710 13:00:00 8
我很感激这方面的任何帮助:)!