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我有像 (1+1),1+(a+1) 这样的表达式的 LR 语法和 LR 表

0:E'->E

1:E->E+T

2:E->T

3: T -> T * F

4:T->F

5: F ->( E )

6:F->身份证

string[,] ActionTable = 
   //+         *       (       )       id   end     E      T       F 
 {   

 {""     ,""     ,"S4"   ,""     ,"S5"   ,""    ,"1"    ,"2"    ,"3"}, // 0
 {"S6"   ,""     ,""     ,""     ,""     ,"AC"  ,""     ,""     ,"" }, // 1
 {"R2"   ,"S7"   ,""     ,"R2"   ,""     ,"R2"  ,""     ,""      ,""},//2                                                              
 {"R4"   ,"R4"   ,""     ,"R4"   ,""     ,"R4"  ,""     ,""     ,""},  // 3                                
 {""     ,""     ,"S4"   ,""     ,"S5"   ,""    ,"8"    ,"2"    ,"3"}, // 4                                
 {"R6"   ,"R6"   ,""     ,"R6"   ,""     ,"R6"  ,""     ,""     ,""},  // 5                               
 {""     ,""     ,"S4"   ,""     ,"S5"   ,""    ,""     ,"9"    ,"3"}, // 6                                
 {""     ,""     ,"S4"   ,""     ,"S5"   ,""    ,""     ,""     ,"10"},// 7                                
 {"S6"   ,""     ,""     ,"S11"  ,""     ,""    ,""     ,""     ,""},  // 8                                
 {"R1"   ,"S7"   ,""     ,"R1"   ,"R1"   ,""    ,""     ,""     ,""},  // 9                                
  {"R3"   ,"R3"   ,""     ,"R3"   ,"R3"   ,""    ,""     ,""     ,""},  //10                                                               
 {"R5"   ,"R5"   ,""     ,"R5"   ,"R5"   ,""    ,""     ,""     ,""}   //11
                        };

我尝试检查像 1+1 或 1+(1*a)+1 这样的表达式,但解析器说这个表达式不正确。

我可以用我的语法做什么来修复它?

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1 回答 1

1

您没有数字的生产规则。

于 2011-05-28T15:47:44.420 回答