5

我正在尝试获取连接到 RSocket+SpringBoot 网络服务器的浏览器的远程 IP。连接是基于 WebSocket 的 RSocket。

网络服务器是 Java-8，SpringBoot-2，使用 RSocket over WebSocket 并将 RequestStreams 发送到浏览器。我将 SpringBoot 自动配置用于 RSocket 设置，因此服务器端的代码非常少 - 见下文。

@Headers and MessageHeader在下面的代码中只是为了看看他们是否有任何可能导致远程 IP 的东西，没有其他原因他们在那里。

我在网上搜索了一个答案 - http 很多，websockets 有一些， RSocket为零。这 - https://github.com/rsocket/rsocket-java/issues/735 - 看起来很有希望，但无法处理 DuplexConnection，所以那里没有雪茄。

有任何想法吗 ？谢谢 ！

应用程序.yml：

spring.rsocket.server:
  mapping-path: /rsocket-test
  transport: websocket

server.port: 8080

测试控制器.java

 /**
     * TODO: get the remote IP address and log.
     * Options:
     * 1. @see <a href="https://github.com/rsocket/rsocket-java/issues/735">Ability to intercept requests and access channel information such as remote address</a>.
     * 2. Inject IP in header by nginx. See if it shows up in the @Headers param here.
     * 3. Browser gets its public IP and adds it to the request object. Doable, but lame
     * 4. (Unlikely) Find a way to access thru this chain of private members: headers.req.rsocket().source.connection.source.connection.connection.channel.remoteAddress
     */
    @MessageMapping("subscribe-topic")
    public Flux<StreamingEvent> subscribeToEventStream(
                @Headers Map<String,Object> hdrs,
                MessageHeaders mh,
                testRequest request) {
        return testService.subscribeTopic(request.getRequestId(), request.getTopic());
    }
4

2 回答 2

1

客户的IP地址在DuplexConnection课堂上可用。您可以RSocketServer像这样添加拦截器：

@Bean
public RSocketServerCustomizer ipCustomizer() {
    return rSocketServer -> rSocketServer.interceptors(registry -> registry.forConnection(new ConnectionInterceptor()));
}

哪里ConnectionInterceptor是：

static class ConnectionInterceptor implements DuplexConnectionInterceptor {
    @Override
    public DuplexConnection apply(Type type, DuplexConnection duplexConnection) {
        SocketAddress socketAddress = duplexConnection.remoteAddress();
        if (socketAddress instanceof InetSocketAddress) {
            InetSocketAddress iso = (InetSocketAddress) socketAddress;
            // Here is the ip: iso.getHostString()
        }
        return duplexConnection;
    }
}
于 2021-05-11T16:02:59.883 回答
0

在我的场景中，我想将远程主机和原始 HTTP 请求标头传递给我的@MessageMapping处理程序。我想出的最好方法是创建自己的NettyRouteProvider并使用所需数据丰富订阅上下文：

@Component
public class MyRouteProvider implements NettyRouteProvider {

    private final String mappingPath;
    private final SocketAcceptor socketAcceptor;
    private final List<RSocketServerCustomizer> customizers;

    @Autowired
    MyRouteProvider(RSocketProperties properties, RSocketMessageHandler messageHandler,
                    ObjectProvider<RSocketServerCustomizer> customizers) {
        this.mappingPath = properties.getServer().getMappingPath();
        this.socketAcceptor = messageHandler.responder();
        this.customizers = customizers.orderedStream().collect(Collectors.toList());
    }

    @Override
    public HttpServerRoutes apply(HttpServerRoutes httpServerRoutes) {
        RSocketServer server = RSocketServer.create(this.socketAcceptor);
        this.customizers.forEach((customizer) -> customizer.customize(server));
        ServerTransport.ConnectionAcceptor connectionAcceptor = server.asConnectionAcceptor();

        return httpServerRoutes.ws(this.mappingPath, (in, out) ->
                connectionAcceptor.apply(new WebsocketDuplexConnection((Connection) in)).then(out.neverComplete())
                        .contextWrite(context -> {
                            String ip = in.headers().get("x-forwarded-for");
                            SocketAddress remoteAddress = ((Connection) in).channel().remoteAddress();
                            
                            if(in.headers().contains("x-forwarded-for")){
                                return context
                                        .put("remoteHost",remoteAddress)
                                        .put(HttpHeaders.class, in.headers())
                                        .put("client-ip", ip);
                            }
                            return context
                                    .put("remoteHost",remoteAddress)
                                    .put(HttpHeaders.class, in.headers());
                        }));
    }

}

在此之后，您将能够在任何 @MessageMapping 方法中从上下文中获取数据，例如：

@MessageMapping("remote-host")
fun remoteHost(): Mono<SocketAddress> {
    return Mono.deferContextual { context ->
        Mono.just(context.get<SocketAddress>("remoteHost"))
    }
}
于 2022-01-22T09:21:30.573 回答