2

我有多个raise ValueError要测试的功能。到目前为止,我的解决方案是:

import pytest
import record

@pytest.fixture(name='raised')
def is_value_error_raised(func, args):
    try:
        func(*args)
        return True
    except ValueError:
        return False


@pytest.mark.parametrize(('func', 'args', 'expected'),
                         ((record.check_length, ('Test', 1, 100), True),
                          (record.check_length, ('', 1, 100), False),
                          ))
def test_length_check(raised, expected):
    assert raised == expected


@pytest.mark.parametrize(('func', 'args', 'expected'),
                         ((record.check_lang_code, ['EN'], True),
                          (record.check_lang_code, ['Test'], False),
                          ))
def test_lang_check(raised, expected):
    assert raised == expected

但在这种方法中,我在每个测试用例中重复函数名称。我试图摆脱它。我想知道是否可以制作类似的东西:

@pytest.mark.parametrize(('func', record.check_lang_code))
@pytest.mark.parametrize(('args', 'expected'),
                         ((['EN'], True),
                          (['Test'], False),
                          ))
def test_lang_check(raised, expected):
    assert raised == expected

这产生ValueError. 有没有办法使用两个参数化标记相互配合?如果不是,我该如何更正此代码?

4

1 回答 1

0

我通过将测试功能与夹具内的测试元素映射来解决我的问题。无论如何,我仍然想知道使用双参数化是否可以达到相同的效果。其他更优雅的解决方案将不胜感激。

import pytest
import record

@pytest.fixture(name='raised')
def is_value_error_raised(request, args):
    try:
        test_name = request.node.function.__name__
        {'test_length_check': record.check_length,
         'test_lang_check': record.check_lang_code,
        }[test_name](*args)
        return True
    except ValueError:
        return False


@pytest.mark.parametrize(('args', 'expected'), (
        (('Test', 1, 100), True),
        (('', 1, 100), False),
))
def test_length_check(raised, expected):
    assert raised == expected


@pytest.mark.parametrize(('args', 'expected'), (
        (['EN'], True),
        (['Test'], False),
))
def test_lang_check(raised, expected):
    assert raised == expected
于 2020-05-01T11:37:50.617 回答