2

我有一个 java 服务器，它通过一个套接字将一些数据发送到一个用 android 开发的客户端。发送的数据被序列化......并且在客户端尝试从 ObjectInputStream 读取时出现以下错误：

 java.lang.ClassNotFoundException: servers.Coordinate    
 at java.lang.Class.classForName(Native Method)
 at java.lang.Class.forName(Class.java:237)
 at java.io.ObjectInputStream.resolveClass(ObjectInputStream.java:2604) 
 at java.io.ObjectInputStream.readNewClassDesc(ObjectInputStream.java:1860)
 java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:840)
 at java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:2080)
 java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:943)
 java.io.ObjectInputStream.readObject(ObjectInputStream.java:2299)
 at java.io.ObjectInputStream.readObject(ObjectInputStream.java:2254)
 at com.Server_1.ClientThread_special.run(ClientThread_special.java:30)
 at java.lang.Thread.run(Thread.java:1096)
 Caused by: java.lang.NoClassDefFoundError: servers.Coordinate
 Caused by: java.lang.ClassNotFoundException: servers.Coordinate in loader dalvik.system.PathClassLoader@43d02e18
 at dalvik.system.PathClassLoader.findClass(PathClassLoader.java:243)

现在这是我在服务器端的代码：

clientSocket = serverSocket.accept();
        System.out.println("S-a conectat clientul de monitorizare!");


        os=new ObjectOutputStream(clientSocket.getOutputStream());
        try{
        while(true){
            coord=(Coordinate)queue.take();
            System.out.println(coord.getLat());
        os.writeObject(coord);

        os.flush();

        }
        }
        catch(Exception e)
        {
            e.printStackTrace();

        }

在客户端我有这个：

public void run() {

    try {
        InetAddress serverAddr = InetAddress.getByName(serverIpAddress);

        Socket socket = new Socket(serverIpAddress, serverPort);

        is=new ObjectInputStream(socket.getInputStream());



            try{
                while(!stop){

            coord=(Coordinate)is.readObject();

            System.out.println("Date de la clientul de monitorizare:"+coord.getLat());

            }

            }
            catch(Exception e)
            {
                e.printStackTrace();
            }

        is.close();

    } catch (UnknownHostException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

这是我的可序列化类，我在客户端和服务器端都有它：

 public class Coordinate implements Serializable{

  private final double lon;

  private final double lat;

  private final int workerId;



  public Coordinate(double lat, double lon, int workerId) {

    this.lat = lat;
    this.lon = lon;

    this.workerId=workerId;
  }

  public double getLon() {
    return lon;
  }

  public double getLat() {
    return lat;
  }
  public int getwId(){
      return workerId;
  }


}

这个类的一个实例是我通过套接字发送的。

编辑：

在服务器上我有以下内容：

包服务器；

导入 java.io.Serializable；

公共类坐标实现可序列化{

  private final double lon;

  private final double lat;

  private final int workerId;



  public Coordinate(double lat, double lon, int workerId) {

    this.lat = lat;
    this.lon = lon;

    this.workerId=workerId;
  }

  public double getLon() {
    return lon;
  }

  public double getLat() {
    return lat;
  }
  public int getwId(){
      return workerId;
  }


}

在客户端，我有以下内容：

包 com.Server_1；

导入 java.io.Serializable；

公共类坐标实现可序列化{

  private final double lon;

  private final double lat;

  private final int workerId;

  public Coordinate(double lat, double lon, int workerId) {

    this.lat = lat;
    this.lon = lon;

    this.workerId=workerId;
  }

  public double getLon() {
    return lon;
  }

  public double getLat() {
    return lat;
  }
  public int getwId(){
      return workerId;
  }


}

我不明白我怎么能把两个包都改成一样的！！！！！！

4

1 回答 1

4

类的包名在服务端和客户端必须相同。我还会将 serialVersionUID 添加到类中。实现可序列化

于 2011-05-20T18:21:43.823 回答