reactjs - 如何获得突变反应？

Question

我在我的 reactjs 应用程序中成功地进行了这种突变，但我想得到响应 graphql 返回但在我的 reactjs 应用程序中，这可能吗？

反应代码：

import { useMutation } from "@apollo/react-hooks";      

const [addStoreToDB, { error }] = useMutation(addStoreMutation);

  if (error) {
    console.log("error:", error);
    return <p>Error :(</p>;
  }

  const handleSubmit = event => {
    event.preventDefault();
    dispatch(addStoreAction(newStore));
    addStoreToDB({
      variables: {
        name: newStore.name,
        address: newStore.address,
        description: newStore.description,
        phone: newStore.phone,
        picture1: newStore.picture1
      },
      refetchQueries: [{ query: getStoresQuery }]
    });
  };

在 GraphQL 中：

mutation {
  addStore (name:"Lorem ipsum", address:"Lorem ipsum", description:"Lorem Ipsum", phone:"555555", picture1:"https://lorem-ipsum") {
    id
  }
}

Answer 1

const [addStoreToDB, { error }] = useMutation(addStoreMutation
    {
      onCompleted: (data) => {
        console.log(data) // the response
      },
      onError: (error) => {
        console.log(error); // the error if that is the case
      },
    }
  );

Answer 2

useMutation 返回的变异函数是一个承诺。所以你可以使用.then和.catch喜欢

 addStoreToDB({...stuff})
     .then(response => {
      //handle response
      })
     .catch(err =>{
     //handle error
    })