我正在使用以下代码通过肥皂调用方法。它运行良好。
private static final String SOAP_ACTION = "http://tempuri.org/GetAuthenticateUser";
private static final String METHOD_NAME = "GetAuthenticateUser";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://stage.mysite.com/FinancialSnapshotService/Service.asmx?WSDL";
// I have tried http://stage.mysite.com/FinancialSnapshotService/Service.asmx also
public void getResults() {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("vstrUserID", "vk@gmail.com");
request.addProperty("vstrPassword", "password");
SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
soapEnvelope.dotNet = true;
soapEnvelope.setOutputSoapObject(request);
HttpTransportSE aht = new HttpTransportSE(URL);
try {
aht.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
aht.call(SOAP_ACTION, soapEnvelope);
SoapObject result = (SoapObject) soapEnvelope.getResponse();
Log.d("WS", String.valueOf(result));
} catch (Exception e) {
e.printStackTrace();
}
}
但是当我尝试将相同的代码用于同一服务器中的其他一些方法时,它给出了ClassCastException: org.ksoap2.SoapFault
. 如果我将行更改SoapObject result = (SoapObject) soapEnvelope.getResponse();
为SoapObject result = (SoapObject)soapEnvelope.bodyIn;
,它会完美运行。谁能告诉我这段代码的基本内容,在哪里使用bodyIn
以及在哪里使用getResponse()
?