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我想在这个查询中添加一个 UNION ，我应该把任何 UNION （不管 UNION 的代码，我只想知道我可以把它放在哪里）在下面的灵活搜索查询中（我是不熟悉语法）

   SELECT DISTINCT {o:pk} FROM 
( 
    {{ 
        SELECT 
            MAX({h.startTime}) AS startTime 
        FROM {CronJobHistory AS h JOIN CronJobResult AS r ON {h.result} = {r.pk} } 
        WHERE {h.cronJobCode} = 'ordersCronJob' AND {r.code} = 'SUCCESS' 
    }} 
) LAST, 
( 
    {{ 
        SELECT 
            MAX({h.startTime}) AS startTime 
        FROM {CronJobHistory as h} 
        WHERE {h.cronJobCode} = 'ordersCronJob' 
    }} 
) CURRENT, {Order       AS o 
       JOIN PaymentMode AS pm ON {pm.pk} = {o:paymentMode} 
       JOIN BaseStore AS b ON {o.store} = {b.PK} 
       JOIN OrderProcess AS op ON {o.pk} = {op.order}
    } 
WHERE (({pm:code} != 'asm'  AND  {op:creationtime} > LAST.startTime        AND {op:creationtime} <= CURRENT.startTime) 
    OR ({pm:code} =  'asm'  AND  {o:asmActivationTime} > LAST.startTime   AND {o:asmActivationTime} <= CURRENT.startTime) )  
    AND {o:originalVersion} IS NULL 
    AND 'rows-eu,rows-es' LIKE CONCAT( '%', CONCAT( {b.uid} , '%' ) ) 
AND {op.processDefinitionName} LIKE 'order-process%'

我试过把它放在最后一行，但它没有编译。

有什么提示吗？

4

1 回答 1

4

对于UNION查询或INNER查询，您需要将各自的查询用双花括号括起来。 

{{..query1..}} UNION {{..query2..}}

检查下面的示例以获取灵活的查询联合示例。

SELECT uniontable.PK, uniontable.CODE FROM
(
   {{
      SELECT {c:PK} as PK, {c:code} AS CODE FROM {Chapter AS c}
      WHERE {c:PUBLICATION} LIKE ?pk
   }}
   UNION ALL
   {{
      SELECT {p:PK} as PK, {p:code} AS CODE FROM {Page AS p}
      WHERE {p:PUBLICATION} LIKE ?pk
   }}
) uniontable

您可以在 https://help.sap.com/viewer/d0224eca81e249cb821f2cdf45a82ace/1905/en-US/8bc36ba986691014b48be171221d1f4f.html找到FlexibleSearch 提示和技巧

希望能帮助到你！

修复了查询的前半部分... 

  SELECT tbl.startTime FROM 
( 
    {{ 
        SELECT 
            MAX({h.startTime}) AS startTime 
        FROM {CronJobHistory AS h JOIN CronJobResult AS r ON {h.result} = {r.pk} } 
        WHERE {h.cronJobCode} = 'ordersCronJob' AND {r.code} = 'SUCCESS' 
    }} 
 UNION 

    {{ 
        SELECT 
            MAX({h.startTime}) AS startTime 
        FROM {CronJobHistory as h} 
        WHERE {h.cronJobCode} = 'ordersCronJob' 
    }} 
) tbl
于 2019-10-24T09:35:29.557 回答