django-views - 我正在尝试将多个模型合并到一个 django 视图中；如何访问上下文 **kwargs

Question

我试过这个：

class MyClass(LoginRequiredMixin, UpdateView, ListView):
    model = models.my_model
    fields = ['first_model_field', 'second_model_field']
    template_name = 'app/template_name.html'
    extra_context = {'second_model': models.second_model.objects.get(pk=self.kwargs['pk']),#didn't work
'third_model':models.third_model.objects.get(pk='pk'),#didn't work
'fourth_model':models.fourth_model.objects.get(foreign_key_id = 'unique_kwarg')}#didn't work.

我也有包含/<int:pk>/kwarg 和/<int:unique_kwarg>/kwarg 的 url。

我无法弄清楚如何引用 url **kwarg 对象。

Answer 1

    def form_valid(self, form):
        form_template_id = self.kwargs.get(self.pk_url_kwarg)
        form.instance.model_id = model.objects.get(pk=form_template_id)
        return super().form_valid(form)

和

    def get_context_data(self, **kwargs):
        """Insert the form into the context dict."""

        if 'unique_kwarg' not in kwargs:
            kwargs['unique_kwarg'] = (self.kwargs.get(self.unique_kwarg))
            kwargs['model_id'] = (model.objects.get(id=self.kwargs.get(self.unique_kwarg)))


        return super().get_context_data(**kwargs)