我要从 .txt 输入中读取并按行排序到数组中(读取:名字、姓氏、等级 1、等级 2、等级 3),但我遇到了问题。我假设我必须为每个人创建数组,但我无法通过对每个行条目进行排序。我了解如何使用拆分的基础知识,但我假设我必须使用嵌套的 for 循环将字符串与双精度数分开,并将每个字符串放在自己的数组中。我不确定如何编译它。
1 回答
0
您可以使用 FileReader 逐行读取。然后,您可以在逗号上拆分结果字符串,并使用 Double.valueOf 来获取您的值。以下示例很简单,但假定文件格式正确:
public class Test {
static class Student {
private String firstName;
private String lastName;
private double math;
private double english;
private double computerScience;
public Student(String firstName, String lastName, double math,
double english, double computerScience) {
this.firstName = firstName;
this.lastName = lastName;
this.math = math;
this.english = english;
this.computerScience = computerScience;
}
@Override
public String toString() {
return "Name: " + firstName + " " + lastName + ", Math: " + math +
", English: " + english + ", Computer Science: " + computerScience;
}
}
public static void main(String[] args) {
BufferedReader reader;
try {
reader = new BufferedReader(new FileReader("/home/username/grades.txt"));
String line = reader.readLine();
while (line != null) {
String[] gradeArray = line.split(",");
Student myStudent = new Student(gradeArray[0], gradeArray[1],
Double.valueOf(gradeArray[2]), Double.valueOf(gradeArray[3]),
Double.valueOf(gradeArray[4]));
System.out.println(myStudent.toString());
line = reader.readLine();
}
}
catch (NumberFormatException|IndexOutOfBoundsException badFile) {
System.out.println("You have a malformed gradebook");
badFile.printStackTrace();
}
catch (IOException e) {
e.printStackTrace();
}
}
}
于 2019-10-01T12:23:27.837 回答