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我的任务是执行两个 Oracle 功能，实现以下目标：

  1. 将 CLOB 作为输入并使用 AES-256 对其进行加密并返回 Encrypted CLOB
  2. 将 Encrypted CLOB 作为输入，使用 AES-256 解密并返回 Decrypted CLOB

CLOB 数据问题很大，函数应该处理好这个问题。

我能够通过第一个函数，它运行良好，即用大量数据加密 CLOB：

create or replace 
function F_ENCRYPT_CLOB (ac_input IN CLOB) return CLOB is
l_clob CLOB;
lb_variable BLOB;
v_key RAW (320);
v_encryption_type PLS_INTEGER := DBMS_CRYPTO.AES_CBC_PKCS5; 
v_iv RAW (320);
l_dest_offset  PLS_INTEGER := 1;
l_src_offset   PLS_INTEGER := 1;
l_lang_context PLS_INTEGER := DBMS_LOB.default_lang_ctx;
l_warning      PLS_INTEGER;
l_step PLS_INTEGER := 1998;
begin
    SELECT VALUE
     INTO v_key
     FROM algparameters
     WHERE name = 'key';
   SELECT VALUE
    INTO v_iv
     FROM algparameters
    WHERE name = 'iv';

dbms_lob.createtemporary(lb_variable, true);


 sys.DBMS_CRYPTO.ENCRYPT(
                 dst => lb_variable,
                 src => ac_input,
                 typ => v_encryption_type,
                 key => v_key,
                 iv => v_iv
                 );

  DBMS_LOB.createTemporary(
    lob_loc => l_clob,
    cache   => TRUE);


  FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(lb_variable) - 1 )/l_step) LOOP
        l_clob := l_clob || UTL_RAW.cast_to_varchar2(UTL_ENCODE.base64_encode(DBMS_LOB.substr(lb_variable, l_step, i * l_step + 1)));
      END LOOP;
   RETURN l_clob;

end F_ENCRYPT_CLOB;

但是我在使用类似步骤解密先前加密的值时遇到了问题：

create or replace 
function F_DECRYPT_CLOB (ac_input IN CLOB) return CLOB is 
  lb_variable CLOB; 
  l_blob BLOB;
  v_key RAW (320);
  v_encryption_type PLS_INTEGER := DBMS_CRYPTO.AES_CBC_PKCS5;
  v_iv RAW (320);
  l_dest_offset  PLS_INTEGER := 1;
  l_src_offset   PLS_INTEGER := 1;
  l_lang_context PLS_INTEGER := DBMS_LOB.default_lang_ctx;
  l_warning      PLS_INTEGER;

  l_raw     RAW(32767);
  l_amt     NUMBER := 7700;
  l_offset  NUMBER := 1;
  l_temp    VARCHAR2(32767);
  l_step PLS_INTEGER := 7700;

begin 
    SELECT VALUE
     INTO v_key
     FROM algparameters
    WHERE name = 'key';
   SELECT VALUE
     INTO v_iv
     FROM algparameters
    WHERE name = 'iv';

    dbms_lob.createtemporary(l_blob, true);

   FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(ac_input) - 1 )/l_amt) LOOP
      DBMS_LOB.read(ac_input, l_amt, l_offset, l_temp);
      l_offset := l_offset + l_amt;
      l_raw    := UTL_ENCODE.base64_decode(l_temp);
      DBMS_LOB.append (l_blob, TO_BLOB(l_raw));
    END LOOP; 

  dbms_lob.createtemporary(lb_variable, true);

 sys.DBMS_CRYPTO.DECRYPT( 
                 dst => lb_variable, 
                 src => l_blob, 
                 typ => v_encryption_type,--dbms_crypto.des_cbc_pkcs5, 
                 key => v_key,
                 iv => v_iv
                 ); 

   return lb_variable; 
end F_DECRYPT_CLOB;

它抛出的错误是：

ORA-06502: PL/SQL: numeric or value error: hex to raw conversion error
ORA-06512: at "SN_PRE_STAGE_415.F_DECRYPT_CLOB", line 33
06502. 00000 - "PL/SQL: numeric or value error%s"
*原因：
*行动：

4

1 回答 1

1

错误来自第 33 行，即：

l_raw    := UTL_ENCODE.base64_decode(l_temp);

该base64_decode函数需要一个 RAW 参数，因此您可以转换您现在拥有的字符串：

l_raw    := UTL_ENCODE.base64_decode(UTL_RAW.cast_to_raw(l_temp));

IE

   FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(ac_input) - 1 )/l_amt) LOOP
      DBMS_LOB.read(ac_input, l_amt, l_offset, l_temp);
      l_offset := l_offset + l_amt;
      l_raw    := UTL_ENCODE.base64_decode(UTL_RAW.cast_to_raw(l_temp));
      DBMS_LOB.append (l_blob, TO_BLOB(l_raw));
    END LOOP;

现在它正在抛出这个

ORA-28817: PL/SQL 函数返回错误。
ORA-06512：在“SYS.DBMS_CRYPTO_FFI”，第 110行 ORA-06512：在“SYS.DBMS_CRYPTO”，
第 64 行
ORA-06512：在“STACKOVERFLOW.F_DECRYPT_CLOB”，第 39 行

您的 base-64 字符串有换行符；那些正在丢弃解码。您可以使用较小的块大小，使用l_amt = 64, 并跳过换行符：

   FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(ac_input) - 1 )/(l_amt + 2)) LOOP
      DBMS_LOB.read(ac_input, l_amt, l_offset, l_temp);
      l_offset := l_offset + l_amt + 2;

l_clob但是通过一个新变量一次性剥离它们可能更简单，更有效：

create or replace 
function F_DECRYPT_CLOB (ac_input IN CLOB) return CLOB is 
  lb_variable CLOB; 
  l_clob CLOB;
  l_blob BLOB;
  ... 
begin 
   ...
    dbms_lob.createtemporary(l_blob, true);

   l_clob := replace(replace(ac_input, chr(13), null), chr(10), null);

   FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(l_clob) - 1 )/l_amt) LOOP
      DBMS_LOB.read(l_clob, l_amt, l_offset, l_temp);
      l_offset := l_offset + l_amt;
      l_raw    := UTL_ENCODE.base64_decode(utl_raw.cast_to_raw(l_temp));
      DBMS_LOB.append (l_blob, TO_BLOB(l_raw));
    END LOOP; 
   ...    
end F_DECRYPT_CLOB;
/

在全：

create or replace 
function F_DECRYPT_CLOB (ac_input IN CLOB) return CLOB is 
  lb_variable CLOB; 
  l_clob CLOB;
  l_blob BLOB;
  v_key RAW (320);
  v_encryption_type PLS_INTEGER := DBMS_CRYPTO.AES_CBC_PKCS5;
  v_iv RAW (320);
  l_dest_offset  PLS_INTEGER := 1;
  l_src_offset   PLS_INTEGER := 1;
  l_lang_context PLS_INTEGER := DBMS_LOB.default_lang_ctx;
  l_warning      PLS_INTEGER;

  l_raw     RAW(32767);
  l_amt     NUMBER := 7700;
  l_offset  NUMBER := 1;
  l_temp    VARCHAR2(32767);
  l_step PLS_INTEGER := 7700;

begin 
    SELECT VALUE
     INTO v_key
     FROM algparameters
    WHERE name = 'key';
   SELECT VALUE
     INTO v_iv
     FROM algparameters
    WHERE name = 'iv';

    dbms_lob.createtemporary(l_blob, true);

   l_clob := replace(replace(ac_input, chr(13), null), chr(10), null);

   FOR i IN 0 .. TRUNC((DBMS_LOB.getlength(l_clob) - 1 )/l_amt) LOOP
      DBMS_LOB.read(l_clob, l_amt, l_offset, l_temp);
      l_offset := l_offset + l_amt;
      l_raw    := UTL_ENCODE.base64_decode(utl_raw.cast_to_raw(l_temp));
      DBMS_LOB.append (l_blob, TO_BLOB(l_raw));
    END LOOP; 

  dbms_lob.createtemporary(lb_variable, true);

 sys.DBMS_CRYPTO.DECRYPT( 
                 dst => lb_variable, 
                 src => l_blob, 
                 typ => v_encryption_type,--dbms_crypto.des_cbc_pkcs5, 
                 key => v_key,
                 iv => v_iv
                 ); 

   return lb_variable; 
end F_DECRYPT_CLOB;
/
于 2019-09-27T14:11:48.097 回答