import datefinder
import pandas as pd
s = "entries are due by January 4th, 2017 at 8:00pm. created 01/15/2005 by ACME Inc. and associates. here Dec. 24th, 1981 at 6pm."
match = datefinder.find_dates(s)
for m in match:
print(m)
2017-01-04 20:00:00
2005-01-15 00:00:00
1981-12-24 18:00:00
以上datefinder用于在字符串中查找日期。例如,January 4th, 2017 at 8:00pm被抓取s并转换为2017-01-04 20:00:00. 现在我只想获取输出print(m)并将其转换为mm包含与print(m). 我用
mm = []
for m in match:
d = pd.Series(m)
mm.append(m)
mm
[datetime.datetime(2017, 1, 4, 20, 0),
datetime.datetime(2005, 1, 15, 0, 0),
datetime.datetime(1981, 12, 24, 18, 0)]
但我希望输出是
mm
[2017-01-04 20:00:00,
2005-01-15 00:00:00,
1981-12-24 18:00:00]
我如何更改我的代码来做到这一点?