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我将一个 XML 文件作为输入，其中包含员工数据和映射值，即工作族 ID 和工作族名称。因此，当员工具有匹配的 Job Family Id 时，我们将替换 Worker_Data 中的 Job Family 名称，并且 Worker_Data 中的其余元素相同。所以我使用了 Identity 匹配，然后调用了需要替换值的元素。但它给了我工作族名的空白。

我已经尝试使用下面的 XSLT 代码来创建地图并为 Job Family ID 匹配调用相同的代码。它只是给我空白而已。不清楚我错过了什么。如果你们中的任何人都可以给我一个关于出了什么问题的提示，这对我真的很有帮助。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:map="http://www.w3.org/2005/xpath-functions/map" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:wd="urn:com.workday/bsvc" exclude-result-prefixes="xs" version="3.0">

    <xsl:mode streamable="no" on-no-match="shallow-skip" use- accumulators="JobFamilyLookup CurrentLookupValue" />

    <xsl:output method="xml" />

    <xsl:accumulator name="CurrentLookupValue" as="xs:string" initial- value="''" streamable="no">
        <xsl:accumulator-rule match="wd:JobFamilyID/text()" select="string()" />
    </xsl:accumulator>

    <xsl:accumulator name="JobFamilyLookup" as="map(xs:string,xs:string)" initial-value="map{}" streamable="no">
        <xsl:accumulator-rule match="wd:JobFamilyName/text()" select="map:put($value, accumulator- 
    before('CurrentLookupValue'),string(.))" />
    </xsl:accumulator>

    <xsl:strip-space elements="*" />

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="wd:Job_Family_ID">
        <xsl:copy>
            <xsl:value-of select="accumulator-before('JobFamilyLookup') ( 
        normalize-space( wd:Job_Family_ID ) )" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="wd:JobFamilyGroupDetails">

    </xsl:template>
</xsl:stylesheet>

输入：

<?xml version="1.0" encoding="UTF-8"?>
<wd:test xmlns:wd="urn:com.workday/bsvc">
<wd:Worker_Data>
    <wd:EmpID>50001</wd:EmpID>
    <wd:Job_Title>Global Talent Director</wd:Job_Title>
    <wd:Job_Family_ID>TAL_TALENT_ACQUISITION</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:Worker_Data>
    <wd:EmpID>50000</wd:EmpID>
    <wd:Job_Title>Executive Assistant</wd:Job_Title>
    <wd:Job_Family_ID>ADMIN_EXECUTIVE_ASSISTANT</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:JobFamilyGroupDetails>
    <wd:JobFamilyDetails>
        <wd:JobFamilyID>ADMIN_EXECUTIVE_ASSISTANT</wd:JobFamilyID>
        <wd:JobFamilyName>ADMIN - Executive Assistant</wd:JobFamilyName>
    </wd:JobFamilyDetails>
    <wd:JobFamilyDetails>
        <wd:JobFamilyID>TAL_TALENT_ACQUISITION</wd:JobFamilyID>
        <wd:JobFamilyName>TAL - Talent Acquisition</wd:JobFamilyName>
    </wd:JobFamilyDetails>
   </wd:JobFamilyGroupDetails>
</wd:test>

预期输出：

<?xml version="1.0" encoding="UTF-8"?>
<wd:test xmlns:wd="urn:com.workday/bsvc">
<wd:Worker_Data>
    <wd:EmpID>50001</wd:EmpID>
    <wd:Job_Title>Global Talent Director</wd:Job_Title>
    <wd:Job_Family_ID>TAL - Talent Acquisition</wd:Job_Family_ID>
</wd:Worker_Data>
<wd:Worker_Data>
    <wd:EmpID>50000</wd:EmpID>
    <wd:Job_Title>Executive Assistant</wd:Job_Title>
    <wd:Job_Family_ID>ADMIN - Executive Assistant</wd:Job_Family_ID>
</wd:Worker_Data>
</wd:test>
4

1 回答 1

1

我会简单地使用一个键：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xpath-default-namespace="urn:com.workday/bsvc"
    exclude-result-prefixes="#all"
    expand-text="yes"
    version="3.0">

  <xsl:key name="details" match="JobFamilyDetails" use="JobFamilyID"/>

  <xsl:mode on-no-match="shallow-copy"/>

  <xsl:template match="Worker_Data/Job_Family_ID[key('details', .)]">
      <xsl:copy>{key('details', .)/JobFamilyName}</xsl:copy>
  </xsl:template>

  <xsl:template match="JobFamilyGroupDetails"/>

</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/ncdD7mJ

至于您对使用流式传输和累加器的请求，因为流式传输仅转发解决该问题的唯一方法是将相关工作人员数据存储在一系列地图中，然后在您尝试使用时在地图中捕获详细信息数据它作为输出相关元素的工人数据映射序列中每个项目的模板中的参数：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:map="http://www.w3.org/2005/xpath-functions/map"
    xmlns:wd="urn:com.workday/bsvc"
    xpath-default-namespace="urn:com.workday/bsvc"
    exclude-result-prefixes="#all"
    version="3.0">

    <xsl:mode on-no-match="shallow-skip" streamable="yes" use-accumulators="#all"/>

    <xsl:output method="xml" indent="yes"/>

    <xsl:accumulator name="current-id" as="xs:string?" initial-value="()" streamable="yes">
        <xsl:accumulator-rule match="JobFamilyDetails/JobFamilyID/text()"
            select="string()"/>
    </xsl:accumulator>

    <xsl:accumulator name="details" as="map(xs:string, xs:string)" initial-value="map{}" streamable="yes">
        <xsl:accumulator-rule match="JobFamilyDetails/JobFamilyName/text()"
            select="map:put($value, accumulator-before('current-id'), string())"/>
    </xsl:accumulator>

    <xsl:accumulator name="workers" as="map(xs:string, xs:string)*" initial-value="()" streamable="yes">
        <xsl:accumulator-rule match="Worker_Data" select="$value, map { }"/>
        <xsl:accumulator-rule match="Worker_Data/EmpID/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'id', string()))"/>
        <xsl:accumulator-rule match="Worker_Data/Job_Title/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'title', string()))"/>
        <xsl:accumulator-rule match="Worker_Data/Job_Family_ID/text()" 
            select="let $wmap := $value[last()]
            return ($value[position() lt last()], map:put($wmap, 'jfid', string()))"/>
    </xsl:accumulator>

    <xsl:template match="/*">
        <xsl:copy>
            <xsl:apply-templates/>
            <xsl:apply-templates select="accumulator-after('workers')" mode="output">
                <xsl:with-param name="details" select="accumulator-after('details')"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

    <xsl:template match=".[. instance of map(*)]" mode="output" expand-text="yes">
        <xsl:param name="details"/>
        <wd:Worker_Data>
            <wd:EmpID>{?id}</wd:EmpID>
            <wd:Job_Title>{?title}</wd:Job_Title>
            <wd:Job_Family_ID>{$details(?jfid)}</wd:Job_Family_ID>
        </wd:Worker_Data>      
    </xsl:template>

</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/pPzifpL/2

在我没有测试过的内存使用方面是否表现良好。

于 2019-05-08T16:07:45.297 回答