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我正在尝试对我的命令进行确认部分，如果您激活该命令，则需要在代码激活之前说“是”。再次出现的问题是消息后面的代码

已确认...请稍候。

在此之后，它完全跳过代码并且什么也不做。当我在 VSC 中编写代码时，async代码部分不是用黄色突出显示的，而是更深的黄色。

我已经尝试删除这部分代码 const async = async () => { 但是除非它连接到异步，否则带有等待的代码无法运行。我试过改变异步的运行方式。 async () => { 结果还是一样。删除开始的异步代码也只会导致命令中断。我已经将大块代码放在代码之外then(collected，但是在命令激活时等待几秒钟后，它立即运行，然后出现值错误。但我希望它在作者说“是”时激活代码

async run(message, args){

if (message.channel instanceof Discord.DMChannel) return message.channel.send('This command cannot be executed here.')

let replyMessage = message.reply('Please make sure that my integration role "Synthibutworse" is above the default role used for this server. Is this correct? [Reply with "YES"] if so. Will expire in 20 seconds...');

let filter = msg => msg.author.id == message.author.id && msg.content.toLowerCase() == 'yes';
message.channel.awaitMessages(filter, {max: 1, time: 20000}).then(collected => {

  message.reply('Confirmed... Please wait.');

  const async = async () => {

  if(!message.member.guild.me.hasPermission(['MANAGE_WEBHOOKS'])) return message.channel.send('I don\'t have the permissions to make webhooks, please contact an admin or change my permissions!')
  if(!message.member.guild.me.hasPermission(['MANAGE_ROLES'])) return message.channel.send('I don\'t have the permissions to make roles, please contact an admin or change my permissions!')
  if (!message.member.hasPermission(['MANAGE_WEBHOOKS'])) return message.channel.send('You need to be an admin or webhook manager to use this command.')
  if (!message.member.hasPermission(['MANAGE_ROLES'])) return message.channel.send('You need to be an admin or role manager to use this command.')

  const avatar = `https://cdn.discordapp.com/attachments/515307677656678420/557050444954992673/Generic5.png`;
  const name2 = "SYNTHIBUTWORSE-1.0WOCMD";

  let woaID = message.mentions.channels.first(); 
  if(!woaID) return message.channel.send("Channel is nonexistant or command was not formatted properly. Please do s!woa #(channelname)"); 
  let specifiedchannel = message.guild.channels.find(t => t.id == woaID.id);; 

  const hook = await woaID.createWebhook(name2, avatar).catch(error => console.log(error))
  await hook.edit(name2, avatar).catch(error => console.log(error))
  message.channel.send("Please do not tamper with the webhook or else the command implied before will no longer function with this channel.")

  var role = message.guild.createRole({
      name: `Synthibutworse marker v1.0`,
      color: 0xcc3b3b,}).catch(console.error);

  specifiedchannel.send("Created role...");

  if(message.guild.roles.name == "Synthibutworse marker v1.0") {
    role.setMentionable(false, 'SBW Ping Set.')
    role.setPosition(1)
    role.setPermissions(['CREATE_INSTANT_INVITE', 'SEND_MESSAGES'])
      .then(role => console.log(`Edited role`))
      .catch(console.error)};

  message.channel.send("Role set up...");

  const sbwrID = message.guild.roles.find(`Synthibutworse marker v1.0`);
  let specifiedrole = message.guild.roles.find(r => r.id == sbwrID.id)

  message.channel.send('Created Role... Please wait.');

  message.guild.specifiedchannel.replacePermissionOverwrites({
    overwrites: [
      {
         id: specifiedrole,
         denied: ['SEND_MESSAGES'],
         allowed: ['VIEW_CHANNEL'],
      },
    ],
      reason: 'Needed to change permissions'
    });

  var bot = message.client
  bot.on('message', function(message) { {
      if(webhook.name == `Synthibutworse marker`) return
      if(message.channel.id == webhook.channelID) return 
  {let bannedRole = message.guild.roles.find(role => role.id === specifiedrole);
  message.member.addRole(bannedRole)};
  }});

}});

}};
module.exports = woa;

我希望该命令以异步方式运行，并在消息作者说“是”时继续执行代码，并且不会在Please wait.消息处停止。

实际发生的是代码没有在Please wait消息之后立即运行。

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1 回答 1

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在您当前的代码中，您声明了一个异步函数，但从不调用它。这就是代码从不运行以及 VSC 将其名称变暗的原因。

解决方案：
将您awaitMessages(...)的.then()回调定义为async：

.then(async collected => {
  // do async stuff
});

为了将来参考，如果您需要在无法将函数定义为异步的地方使用异步代码，请使用以下设置：

(async function() {
  // do async stuff
})();
于 2019-05-04T18:24:45.627 回答