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首先感谢所有读者。

问题如下。

int MaxANum = 5;
int MaxBNum = 3;
int MaxENum = 8;

int ANum = 3;
int BNum = 2;
int ENum = 5;

range TTRange = 1..(MaxANum+MaxBNum);
range TRange = 1..(ANum+BNum);
range ARange = 1..ANum;
range BRange = 1..BNum;

range TERange = 1..MaxENum;
range ERange = 1..ENum;

M[TTRange][TERange] = [[**0, 1, 1, 0, 1**, 1, 0, 1] -> 1st ANum
                    [**1, 1, 0, 0, 1**, 0, 0, 1] -> 2nd ANum
                    [**0, 0, 1, 0, 1**, 0, 1, 0] -> 3rd ANum
                    [0, 1, 0, 0, 1, 1, 1, 0] -> 4th ANum
                    [1, 1, 0, 1, 0, 1, 0, 1] -> 5th ANum
                    [**1, 0, 0, 1, 1**, 0, 0, 0] -> 1st BNum
                    [**0, 0, 1, 0, 0, 0**, 1, 1] -> 2nd BNum
                    [1, 1, 0, 0, 0, 0, 0, 1]]; -> 3rd BNum

在这种情况下，我想通过选择某些低点和列来改革矩阵。

就像...

M1[TRange][ERange] = [[0, 1, 1, 0, 1] -> 1st ANum
                    [1, 1, 0, 0, 1] -> 2nd ANum
                    [0, 0, 1, 0, 1] -> 3rd ANum
                    [1, 0, 0, 1, 1] -> 1st BNum
                    [0, 0, 1, 0, 0] -> 2nd BNum

我是 CPLEX 和计算机编码的初学者。请告诉我，如何获得此代码。非常感谢您的阅读。

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1 回答 1

2

我不太确定您的输入与所需的输出有何关联，但此代码段可能会有所帮助：

range TTRange = 1..8;
range TRange = 1..5;
range TERange = 1..8;
range ERange = 1..5;

int M[TTRange][TERange] = [[0, 1, 1, 0, 1, 1, 0, 1],
                           [1, 1, 0, 0, 1, 0, 0, 1],
                           [0, 0, 1, 0, 1, 0, 1, 0],
                           [0, 1, 0, 0, 1, 1, 1, 0],
                           [1, 1, 0, 1, 0, 1, 0, 1],
                           [1, 0, 0, 1, 1, 0, 0, 0],
                           [0, 0, 1, 0, 0, 0, 1, 1],
                           [1, 1, 0, 0, 0, 0, 0, 1]];

int M1[t in TRange][e in ERange] = M[t][e];

它产生这个子矩阵：

 M1 = [[0 1 1 0 1]
       [1 1 0 0 1]
       [0 0 1 0 1]
       [0 1 0 0 1]
       [1 1 0 1 0]]

“技巧”是在 的索引集中进行选择M1。

于 2019-05-02T05:58:52.117 回答