c# - MySqlConnection = new MySqlConnection(string) 不工作

Question

这是我在 Visual Studio 中连接到 Unity3d 的代码：

public void SetupSQLConnection()
{
    Debug.Log("Connection Function Started");
    if (connection == null)
    {
        Debug.Log("If connection == null");
        try
        {
            Debug.Log("Try block started");
            string connectionString = "Server=localhost;" + "Database=therapygame;" + "UID=root;" + "Password=;";
            Debug.Log("string set");
            connection = new MySqlConnection(connectionString);
            Debug.Log("new MySqlConnection");
            connection.Open();
            Debug.Log("connection");
        }
        catch (MySqlException ex)
        {
            Debug.LogError("MySQL Error: " + ex.ToString());
        }
    }
}

控制台字符串一直打印到“字符串集”，但其余部分不打印。

这是 Unity 中的错误：

KeyNotFoundException：给定的键不在字典中。System.Collections.Generic.Dictionary`2[System.String,System.Object].get_Item（System.String 键）（在 /Users/builduser/buildslave/mono/build/mcs/class/corlib/System.Collections.Generic /Dictionary.cs:150) MySql.Data.MySqlClient.MySqlConnectionStringBuilder.get_Database () MySql.Data.MySqlClient.MySqlConnection.set_ConnectionString (System.String 值) MySql.Data.MySqlClient.MySqlConnection..ctor (System.String connectionString) ( wrapper remoting-invoke-with-check) MySql.Data.MySqlClient.MySqlConnection:.ctor (string) mysql.SetupSQLConnection () (at Assets/mysql.cs:31) fire_rate.Start () (at Assets/fire_rate.cs: 18)

score 0 · Accepted Answer

@Dhansushka Dayawansha

我实施了您的更改，但收到了一个新错误。我很高兴我克服了第一个错误！我尝试自己寻找解决这个新错误的方法，但无济于事。这是控制台输出：

NullReferenceException: Object reference not set to an instance of an object
System.Data.Common.DbConnectionStringBuilder.Remove (System.String keyword)
MySql.Data.MySqlClient.MySqlConnectionStringBuilder.Remove (System.String keyword)
MySql.Data.MySqlClient.MySqlConnectionStringOption.Clean (MySql.Data.MySqlClient.MySqlConnectionStringBuilder builder)
MySql.Data.MySqlClient.MySqlConnectionStringBuilder.SetValue (System.String keyword, System.Object value)
MySql.Data.MySqlClient.MySqlConnectionStringOption.<.ctor>b__0 (MySql.Data.MySqlClient.MySqlConnectionStringBuilder msb, MySql.Data.MySqlClient.MySqlConnectionStringOption sender, System.Object value)
MySql.Data.MySqlClient.MySqlConnectionStringBuilder.set_Item (System.String keyword, System.Object value)
MySql.Data.MySqlClient.MySqlConnectionStringBuilder.set_Server (System.String value)
mysql.SetupSQLConnection () (at Assets/mysql.cs:31)
fire_rate.Start () (at Assets/fire_rate.cs:18)

mysql.cs 的第 31 行：

connBuilder.Server = "localhost";

fire_rate.cs 的第 18 行：

GameObject.Find("MySQL").GetComponent<mysql>().SetupSQLConnection();

score 0 · Accepted Answer

尝试这个

MySqlConnectionStringBuilder connBuilder = new MySqlConnectionStringBuilder();

                    connBuilder.Server = "localhost";
                    connBuilder.UserID = "root";
                    connBuilder.Database = "therapygame";
                    connBuilder.Password = "";
                    connBuilder.OldGuids = true;

                connection = new MySqlConnection(connBuilder.ConnectionString);

c# - MySqlConnection = new MySqlConnection(string) 不工作

2 回答 2

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