api - 如何只显示有值的字段，隐藏没有值的字段？

Question

我试图让这段代码只显示有值的字段，任何没有值的字段都不打算显示。它似乎不起作用

知道我做错了什么吗？

我的简单测试表在这里http://www.healthybrighton.co.uk/wse/node/1844

/**
 * Build a table of submitted values
 *
 * @param $form_vals array Submitted form data
 * @param $select_mapping array Map select components to their value|label chocies
 * @return HTML of the themed table
 */       
function _format_form_state($form_vals = array(), $select_mapping) {
  $output = '';  
  $header = array();
  $rows = array();    

  if (!empty($form_vals)) {

    foreach ($form_vals as $component_name => $component_value) {
      $rows = array_merge(
        $rows,
        _add_component_row(
          $component_name,
          $component_value,
          0,
          $select_mapping
        )
      );
    }
  }



  $output .= theme('table', $header, $rows);
  return $output;
}

Answer 1

/**
 * Build a table of submitted values
 *
 * @param $select_mapping array Map select components to their value|label chocies
 * @param $values array Submitted form data
 * @return HTML of the themed table
 */
function _format_form_state($select_mapping, $values = array()) {
  $header = array(t('First'), t('Second'), t('Third'), t('Fourth'));
  $rows = array();

  foreach ($values as $cname => $cval) {
    $rows[] = array($cname, $cval, 0, $select_mapping);
  }

  return theme_table($header, $rows);
}

$select_mapping 应该是函数中的第一个参数。具有默认值的参数不应位于没有默认值的参数之前。