php - 如何在另一个文件中的函数中传递命名空间？

Question

这是我的代码和我遇到的问题：

// index.php

require "/var/www/functions.php";
use Microsoft\Graph\Graph;
use Microsoft\Graph\Model;
$microsoftGraph = new Graph();

test();



// functions.php

function test($microsoftGraph) {
    $create = $microsoftGraph->createRequest('POST', $create)
    ->setReturnType(Model\Event::class) // This is where I'm having a problem
    ->execute();
}

错误是说：

PHP 致命错误：未捕获的错误：在...中找不到类“事件”

---

但是......如果我use像这样把它放在我的functions.php中，它可以工作：

use Microsoft\Graph\Graph;
use Microsoft\Graph\Model;

function test($microsoftGraph) {
    $create = $microsoftGraph->createRequest('POST', $create)
    ->setReturnType(Model\Event::class) // This is where I'm having a problem
    ->execute();
}

但我怎样才能“通过”或不放入use文件中functions.php？