sql - SQL - 如何从同一列中的行值获取列 (SQL Server 2016)

Question

我需要从一列的行值派生列。

这是行数据。

CustomerID  Activity    Date
10001       Active      2018-06-21
10001       Inactive    2018-06-25
10001       Active      2018-08-22
10001       Inactive    2018-10-06

这是我想要得到的输出：

CustomerID  ActiveDate      InactiveDate
10001       2018-06-21      2018-06-25
10001       2018-08-22      2018-10-06

请帮忙！谢谢！

Answer 1

您可以尝试在子查询中创建行号group by CustomerID,Activity，然后执行条件聚合函数。

SELECT CustomerID,
       MAX(CASE WHEN Activity = 'Active' THEN Date END) ActiveDate,
       MAX(CASE WHEN Activity = 'Inactive' THEN Date END) InactiveDate
FROM (
    SELECT *,ROW_NUMBER() OVER(PARTITION BY CustomerID,Activity ORDER BY Date ) rn
    FROM T
)t1
group by CustomerID,rn

sqlfiddle

Answer 2

你的逻辑有点不清楚。如果您想要下一个“非活动”日期：

select CustomerID, date as active_date, inactive_date
from (select t.*,
             min(case when activity = 'Inactive' then date end) over (partition by CustomerID order by date desc) as inactive_date
      from t
     ) t
where activity = 'Active';