1

我是 k6 的新手,对 JS 很陌生。我正在尝试从我从 DB 中的列导出的平面文件中读取列表。我想打开这个文件并遍历列表,将每个项目附加为我的 HTTP 调用的查询参数。我无法弄清楚如何进行。

例如,如果这是我的文件:

员工.txt

01111
02222
06666
04444
09999

& 这是我的 k6 脚本(perf-employee.js

import http from "k6/http";
import { sleep } from "k6";

export let options = {
  vus: 3,
  duration: "5s" 
};

var data = {some type of parsing her?}.open("./employees.txt");

export default function() {
  http.get("http://www.example.com/employee?employee_num={number-here}“);
  sleep(1);
};

任何关于前进方向的指导将不胜感激。

4

1 回答 1

4

open() 返回一个简单的字符串(如果您使用该标志,则返回一个二进制文件),因此您可以通过使用 JavaScript方法b将其转换为一个数组(它自己的数组行中的每一行)来解析它。String.split()或者,如果您想读取更复杂的数据文件,请使用 JSON 和JSON.parse()方法将其直接转换为 JavaScript 对象 - 请查看上面链接中的第一个示例。

然后通过使用 k6 的执行上下文变量,您可以执行以下操作:

import http from "k6/http";
import { sleep } from "k6";

var data = open("./employees.txt").split(/\r?\n/);

export let options = {
    vus: 3,
    duration: "5s"
};


export default function () {
    var employee = data[__ITER % data.length];
    console.log(`VU ${__VU} on iteration ${__ITER} has employee ID ${employee}...`)
    http.get(`http://www.example.com/employee?employee_num=${employee}`);
    sleep(1);
};

你应该看到类似这样的脚本输出:

INFO[0001] VU 2 on iteration 0 has employee ID 01111... 
INFO[0001] VU 1 on iteration 0 has employee ID 01111... 
INFO[0001] VU 3 on iteration 0 has employee ID 01111... 
INFO[0002] VU 2 on iteration 1 has employee ID 02222... 
INFO[0002] VU 1 on iteration 1 has employee ID 02222... 
INFO[0002] VU 3 on iteration 1 has employee ID 02222... 
INFO[0003] VU 2 on iteration 2 has employee ID 06666... 
INFO[0003] VU 3 on iteration 2 has employee ID 06666... 
INFO[0003] VU 1 on iteration 2 has employee ID 06666... 
INFO[0004] VU 2 on iteration 3 has employee ID 04444... 
INFO[0004] VU 1 on iteration 3 has employee ID 04444... 
INFO[0004] VU 3 on iteration 3 has employee ID 04444... 
INFO[0005] VU 2 on iteration 4 has employee ID 09999... 
INFO[0005] VU 1 on iteration 4 has employee ID 09999... 
INFO[0005] VU 3 on iteration 4 has employee ID 09999... 
于 2018-09-03T07:01:41.127 回答