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您好，我正在尝试创建一个自动查询，显示月至今、年至今和周至今，并为每个查询创建一个列。如果生产日期是最大值 - 存款的最小生产日期总和，我需要合计余额金额。这会给我一个 YTD 专栏。如果有人有任何想法，我还需要做月至今和周至今。对此的任何帮助将不胜感激。谢谢！

PS 我正在使用 microsoft sql server management studio 这是我目前所拥有的：

select SUM([curr_bal_amt]) as total_amt , [prod_dt] as date123
from [dbo].[DEPOSIT_TEST]
group by [prod_dt];

这会产生如下图表：

在此处输入图像描述

总的来说，我需要将年初至今计算为减去我拥有的最大日期减去我拥有的最小日期。稍后当我导入更多数据时，我需要执行 mtd 和 wtd。谢谢

编辑：我正在寻找使用我当前的表格，所以也许编辑这个表格会有所帮助，因为我忘了提到我有 3 天的数据空白。

-对于我的 prod_dt 列，如果 prod_dt 相同，我必须对多个余额求和。是否有一个简单的查询来减去最近日期的 curr_balance amt 总和 - 上个月 curr_balance amt 总和的第一个日期。感谢您的帮助肖恩非常感谢！

这是我某天的数据导入示例之一

如果您可以使用我的专栏名称，那将是非常有益的，这样我可以更好地学习。谢谢！我的表的名称是 Deposit_Test ，列名就像图片中的一样。再次感谢你

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1 回答 1

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这应该让您对如何获得这些总数有一个很好的了解。我不知道您在表中还需要哪些其他数据，但您应该能够修改以下查询以获取它。

SQL小提琴

MS SQL Server 2017 架构设置：

/********************************CALENDAR********************************/
/* 
  My original answer made use of a Calendar Table, but I realized it 
  was overkill for this situation. I still think every database should
  have both a Calendar Table and a Numbers Table. They are both very 
  useful. I use the ct here just to populate my test table, but I've 
  left some very basic creation to show you how it can be done. Calcs 
  done here allow your final query to JOIN to it and avoid RBAR to be 
  more set-based, and save a lot of processing for large tables.  
  NOTE: This original date table concept is from Aaron Bertrand.
*/

CREATE TABLE datedim (
      theDate           date        PRIMARY KEY
    , theDay            AS DATEPART(day, theDate)           --int
    , theWeek           AS DATEPART(week, theDate)          --int 
    , theMonth          AS DATEPART(month, theDate)         --int
    , theYear           AS DATEPART(year, theDate)          --int
    , yyyymmdd          AS CONVERT(char(8), theDate, 112)   /* yyyymmdd */
);

/************************************************************************/
/* 
  Use the catalog views to generate as many rows as we need. This example
  creates a date dimension for all of 2018.
*/
INSERT INTO datedim ( theDate ) 
SELECT d
FROM (
    SELECT d = DATEADD(day, rn - 1, '20180101')
    FROM 
    (
        SELECT TOP (DATEDIFF(day, '20180101', '20190101')) 
            rn = ROW_NUMBER() OVER (ORDER BY s1.object_id)
        FROM sys.all_objects AS s1
        CROSS JOIN sys.all_objects AS s2
        ORDER BY s1.object_id
    ) AS x
) AS y;
/************************************************************************/

/***** TEST TABLE SETUP *****/
CREATE TABLE t1 ( id int identity, entryDate date, cnt int) ;

INSERT INTO t1 (entryDate, cnt)
SELECT theDate, 2
FROM datedim
;

/* Remove a few "random" records to test our counts. */
DELETE FROM t1 
WHERE datePart(day,entryDate) IN (10,6,14,22) OR datepart(month,entryDate) = 6
;

主要查询：

/* Make sure the first day or our week is consistent. */
SET DATEFIRST 7 ; /* SUNDAY */ 

/* Then build out our query needs with CTEs. */
; WITH theDate AS (
  SELECT d.dt FROM ( VALUES ( '2018-05-17' ) ) d(dt) 
)
, base AS (
  SELECT t1.entryDate
    , t1.cnt
    , theDate.dt
    , datepart(year,theDate.dt) AS theYear
    , datepart(month,theDate.dt) AS theMonth
    , datepart(week,theDate.dt) AS theWeek
  FROM t1
  CROSS APPLY theDate
  WHERE t1.EntryDate <= theDate.dt
    AND datePart(year,t1.EntryDate) = datePart(year,theDate.dt)
)
/* Year-to-date totals */
, ytd AS ( 
  SELECT b.theYear, sum(cnt) AS s
  FROM base b
  GROUP BY b.theYear
)
/* Month-to-date totals */
, mtd AS (
  SELECT b2.theYear, b2.theMonth, sum(cnt) AS s
  FROM base b2
  WHERE b2.theMonth = datePart(month,b2.EntryDate)
  GROUP BY b2.theYear, b2.theMonth
)
/* Week-to-date totals */
, wtd AS (
  SELECT b3.theYear, b3.theMonth, sum(cnt) AS s
  FROM base b3
  WHERE b3.theWeek = datePart(week,b3.EntryDate)
  GROUP BY b3.theYear, b3.theMonth
)
SELECT blah = 'CountRow'
  , ytd.s AS ytdAmt
  , mtd.s AS mtdAmt
  , wtd.s AS wtdAmt
FROM ytd 
CROSS APPLY mtd
CROSS APPLY wtd

结果：

|     blah | ytdAmt | mtdAmt | wtdAmt |
|----------|--------|--------|--------|
| CountRow |    236 |     28 |      8 |

同样，您需要获取的数据可能会改变整个查询，但这应该指向正确的方向。您可以使用每个 CTE 来验证 YTD、MTD 和 WTD 总计。

于 2018-07-06T20:50:14.550 回答