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如果我有 2 个级别的变量(条件)并且想要创建一个模型。矩阵 R 会自动将条件B 分配为设计矩阵中的术语。

condition <- as.factor( c("A","A","A","B","B","B"))
df <- data.frame(condition)
design <- model.matrix( ~ condition)

> df
  condition
1         A
2         A
3         A
4         B
5         B
6         B


> design
  (Intercept) conditionB
1           1          0
2           1          0
3           1          0
4           1          1
5           1          1
6           1          1
attr(,"assign")
[1] 0 1
attr(,"contrasts")
attr(,"contrasts")$condition
[1] "contr.treatment"

问题:我希望得到与条件A 相关的结果。如何在 model.matrix() 中指定它?

(一种解决方法是反转生成的 FC)

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2 回答 2

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是你想要的结果吗?

df <- data.frame(condition)
design <- model.matrix( ~ condition-1)
design
  conditionA conditionB
1          1          0
2          1          0
3          1          0
4          0          1
5          0          1
6          0          1
attr(,"assign")
[1] 1 1
attr(,"contrasts")
attr(,"contrasts")$`condition`
[1] "contr.treatment"
于 2018-12-17T14:07:36.510 回答
0

您可以使用该C函数来确定要考虑的基数:

以 A 为底:

 model.matrix(~C(condition,base=1))
  (Intercept) C(condition, base = 1)2
1           1                       0
2           1                       0
3           1                       0
4           1                       1
5           1                       1
6           1                       1
attr(,"assign")
[1] 0 1
attr(,"contrasts")
attr(,"contrasts")$`C(condition, base = 1)`
  2
A 0
B 1

以 B 为底:

model.matrix(~C(condition,base=2))
  (Intercept) C(condition, base = 2)1
1           1                       1
2           1                       1
3           1                       1
4           1                       0
5           1                       0
6           1                       0
attr(,"assign")
[1] 0 1
attr(,"contrasts")
attr(,"contrasts")$`C(condition, base = 2)`
  1
A 1
B 0
于 2018-07-03T09:54:18.627 回答