4

我在我的 Angular 项目中使用Redux Offline，现在我想在离线模式下启用取消发件箱中的项目。基本上，我只想过滤发件箱数组以删除我想取消/修改的项目。

我的问题是我在顶级减速器中收到的状态缺少（未定义）。在 Redux Dev 工具中可以看到离线，也可以通过 NgRedux.select() 和 NgRedux.getState() 获取。

减速器中收到的状态中不存在 redux offline 是否有原因？我可以添加它，然后通过减速器更改它吗？或者是否有另一个可以访问和修改发件箱？

包.json：

"dependencies": {
 "@angular-redux/router": "^7.0.0",
 "@angular-redux/store": "^9.0.0",
 "@angular/animations": "^6.0.3",
 "@angular/common": "^6.0.3",
 "@angular/compiler": "^6.0.3",
 "@angular/core": "^6.0.3",
 "@angular/forms": "^6.0.3",
 "@angular/http": "^6.0.3",
 "@angular/platform-browser": "^6.0.3",
 "@angular/platform-browser-dynamic": "^6.0.3",
 "@angular/pwa": "^0.6.7",
 "@angular/router": "^6.0.3",
 "@angular/service-worker": "^6.0.3",
 "@redux-offline/redux-offline": "^2.3.3",
 "core-js": "^2.5.7",
 "reduce-reducers": "^0.3.0",
 "redux": "^4.0.0",
 "redux-observable": "1.0.0-alpha.2",
 "rxjs": "^6.2.0",
 "rxjs-compat": "^6.2.0",
 "zone.js": "^0.8.26"
},
"devDependencies": {
 "redux-devtools-extension": "^2.13.2",
 "@angular-devkit/build-angular": "^0.6.7",
 "@angular/cli": "^6.0.7",
 "@angular/compiler-cli": "^6.0.3",
 "@angular/language-service": "^6.0.3",
 "@types/jasmine": "^2.8.8",
 "@types/jasminewd2": "~2.0.3",
 "@types/node": "^8.10.18",
 "codelyzer": "^4.3.0",
 "jasmine-core": "~2.99.1",
 "jasmine-spec-reporter": "~4.2.1",
 "karma": "~1.7.1",
 "karma-chrome-launcher": "~2.2.0",
 "karma-coverage-istanbul-reporter": "^1.4.3",
 "karma-jasmine": "^1.1.2",
 "karma-jasmine-html-reporter": "^0.2.2",
 "opn-cli": "^3.1.0",
 "protractor": "^5.3.2",
 "ts-node": "~5.0.1",
 "tslint": "~5.9.1",
 "typescript": "~2.7.2"
}

如果您需要更多信息，请写评论。

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1 回答 1

5

redux-offline动态注入它自己的减速器，因此您将无法通过顶级减速器访问它。redux-offline通过配置公开它的队列，这将允许您更新发件箱以删除/添加操作。如果您想在用户离线时删除离线操作，我建议使用特定操作类型（例如'CANCEL_OFFLINE_ACTION'）进行离线操作调用并处理它queue.enqueue以删除您不想传播的发件箱中的操作。

这是一个粗略的例子：

// the action to dispatch
const action = {
  type: 'CANCEL_OFFLINE_ACTION',
  payload: {
    id: 123,
  },
  meta: {
    offline: {
      effect: {
        url: ''
      },
    },
  },
};

// the custom enqueue action
function enqueue(outbox, incomingAction) {
  return incomingAction.type !== 'CANCEL_OFFLINE_ACTION' ? [...outbox, incomingAction] :
    outbox.filter(
      outboxAction => outboxAction.payload.id !== incomingAction.payload.id,
    );
}

于 2018-06-25T09:09:49.153 回答