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我受到 Unity3d 3 新安全措施的限制，无法将 LitJson 用于 Web Player 应用程序，否则将无法编译。

有没有一种简单的方法可以将此输出序列化为对象（userEcoGet.text 的内容）：

{"building_id":"1","building_level":"0","workers":"0","building_health":"100"}{"building_id":"2","building_level":"0","workers":"0","building_health":"100"}...{"building_id":"32","building_level":"0","workers":"0","building_health":"100"}

此代码仅从 JSON 输入第一个对象：

using UnityEngine;
using System.Collections;
using LitJson;
...
public EcoData localEcoData;
...
localEcoData = JsonMapper.ToObject<EcoData>(userEcoGet.text);
...
public class EcoData
{
    public string building_id;
    public string building_level;
    public string workers;
    public string building_health;
}

将 localEcoData 转换为数组会导致缺少构造函数错误。而且我只是不知道如何在这种情况下正确嵌套构造函数，甚至不确定它是否会有所帮助。

在这一点上，我求助于使用 JsonReader 并手动填写对象。任何帮助，将不胜感激。谢谢你。

编辑：这太疯狂了，今天一整天都因为我对自己造成的糟糕的 JSON 格式而被杀死......

现在完美运行，localEcoData[1,2...32] 是一个对象数组，所有元素均可访问：

public EcoData[] localEcoData;
...
localEcoData = JsonMapper.ToObject<EcoData[]>(userEcoGet.text);

我所要做的就是在处理 MySql 的 PHP 页面上正确编写 JSON 并以有序的方式传输回 Unity。我直接回显而不使用数组进行传输。现在输出看起来像这样并且效果很好：

[{"building_id":"1","building_level":"0","workers":"0","building_health":"100"}{"building_id":"2","building_level":"0","workers":"0","building_health":"100"}...{"building_id":"32","building_level":"0","workers":"0","building_health":"100"}]

谢啦！

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1 回答 1

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我怀疑问题出在您的 JSON 本身。它的格式不正确。要将其解析为 JSON 数组，您需要采用以下格式：

{
    result:[
                {"building_id":"1","building_level":"0","workers":"0","building_health":"100"},
                {"building_id":"2","building_level":"0","workers":"0","building_health":"100"},...
                {"building_id":"32","building_level":"0","workers":"0","building_health":"100"}
           ]
}

如果您无法控制 JSON，则可能需要拆分字符串并将每个字符串视为单个 JSON 对象，并将数组中的每个元素转换为您的 C# 对象类型。

于 2011-02-09T21:29:09.753 回答