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作为一个完整的初学者，我真的希望我在这里遗漏了一些明显的东西，并且有经验的人可以很容易地指出我的错误。

我正处于创建一些 Django 模型的第一步，并且无法弄清楚如何解决我在尝试进行迁移时遇到的错误。根据我的研究，这个错误看起来很模糊。我不知道说没有属性“模型”是什么意思。

这是回溯：

Traceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\__init__.py", line 371, in execute_from_command_line
utility.execute()
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\__init__.py", line 365, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 288, in run_from_argv
self.execute(*args, **cmd_options)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 332, in execute
self.check()
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 364, in check
include_deployment_checks=include_deployment_checks,
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 351, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\checks\registry.py", line 73, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\contrib\admin\checks.py", line 22, in check_admin_app
errors.extend(site.check(app_configs))
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\contrib\admin\sites.py", line 79, in check
if modeladmin.model._meta.app_config in app_configs:
AttributeError: 'Book' object has no attribute 'model'

这是模型代码：

class Author(models.Model):
    name = models.CharField(max_length=80, blank=False, null=False, unique=True)

class Book(models.Model):
    title = models.CharField(max_length=150)
    description = models.TextField(blank=True, null=True)
    series = models.CharField(max_length=150, blank=True, null=True)
    authors = models.ManyToManyField(Author, blank=True)
    finished = models.BooleanField(default=False, verbose_name="Finished")
    # image = models.ImageField()

    def list_authors(self):
        return ", ".join([author.name for author in self.authors.all()])

class Narrator(models.Model):
    narrator = models.CharField(max_length=80)

class Audiobook(Book):
    length = models.TimeField(blank=False, null=False)
    narrator = models.ForeignKey(Narrator, on_delete=models.SET_NULL, blank=False, null=True)

我已经阅读了一些教程，并阅读了我认为可能相关的任何 Django 文档，但我仍然缺少一些东西。任何想法或一般指针将不胜感激。

编辑：添加我的 admin.py。我对此进行了全部评论并且迁移工作正常，但是在尝试运行另一个迁移时我仍然发现相同的错误，以及类似的错误，但不是说没有属性'models'，而是说没有属性'urls'

from django.contrib import admin
from .models import (Author, Book, Narrator, Audiobook)

# Register your models here.

admin.site.register(Author, Book)
admin.site.register(Narrator, Audiobook)
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2 回答 2

1

尝试一一注册模型，如下所示：

admin.site.register(Author)
admin.site.register(Narrator)
admin.site.register(Book)
admin.site.register(Audiobook)
于 2019-05-28T08:51:29.403 回答
0

Django 的文档很容易通过示例来理解。

您的 admin.py 必须与此类似：

from django.contrib import admin
from .models import Author, Book, Narrator, Audiobook
class AuthorAdmin(admin.ModelAdmin):
   fields = ['name']
class BookAdmin(admin.ModelAdmin):
   fields = ['title', 'description', ]

# Register your models here.

admin.site.register(Author, Book)
admin.site.register(Narrator, Audiobook)

您可以在此处查看基本示例以了解教程第 7 部分。

于 2018-01-13T21:40:28.280 回答