python - 递减 for 循环

Question

我想要一个像这样的for循环：

for counter in range(10,0):
       print counter,

并且输出应该是 10 9 8 7 6 5 4 3 2 1

score 107 · Accepted Answer

107

a = " ".join(str(i) for i in range(10, 0, -1))
print (a)

于 2011-01-22T11:00:31.200 回答

score 55 · Accepted Answer

查看range文档，您必须定义一个否定步骤：

>>> range(10, 0, -1)
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1]

score 17 · Accepted Answer

17

你需要给范围一个-1步

 for i in range(10,0,-1):
    print i

于 2011-01-22T11:02:07.087 回答

score 11 · Accepted Answer

11

for i in range(10,0,-1):
    print i,

range() 函数将包含第一个值并排除第二个值。

于 2015-09-10T21:17:16.250 回答

score 1 · Accepted Answer

1

范围步长应为 -1

   for k in range(10,0,-1):
      print k

于 2015-06-30T07:21:28.330 回答

5 回答 5